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Algebra, STD2 EQ-Bank 38

A train departs from Town X at 1:00 pm to travel to Town Y. Its average speed for the journey is 80 km/h, and it arrives at 4:00 pm. A second train departs from Town X at 1:20 pm and arrives at Town Y at 3:30 pm.

What is the average speed of the second train? Give your answer to the nearest kilometre per hour.   (2 marks)

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\(\text{111 km/h}\)

Show Worked Solution

\(\text{Distance between towns X and Y using first train}\)

\(\text{Time taken by first train = 3 hours}\)

\(\text{Distance}=\text{speed}\times\text{time}=80\times 2=240\ \text{km}\)
 

\(\text{Time taken by second train = 2 hours 10 minutes.}\)

\(\text{2 hours 10 minutes = }\dfrac{130}{60}=\dfrac{13}{6}\ \text{hours.}\)

\(\text{Find speed of second train using}\ \ s=\dfrac{d}{t}:\)

\(s=\dfrac{240}{\frac{13}{6}}=240\times \dfrac{6}{13}=110.769…\)

\(\therefore\ \text{The average speed of the second train is 111 km/h (nearest km/h).}\)

Filed Under: Applications: BAC, D=SxT and Medication, Applications: BAC, Medicine and D=S x T Tagged With: Band 5, smc-6235-20-\(d=s\times t\), smc-6509-20-\(d=s \times t\)

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