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Calculus, EXT1 EQ-Bank 28

Given the differential equation  \(\dfrac{d y}{d x}=-\dfrac{x}{y e^{x^2}}\),  determine the particular solution that passes through the point \((0,1 )\).   (3 marks)

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\(y=e^{-\tfrac{x^2}{2}}\)

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\(\dfrac{d y}{d x}\) \(=-\dfrac{x}{y e^{x^{2}}}\)
\(\displaystyle \int y\, d y\) \(=-\displaystyle \int x e^{-x^2}\, d x\)
\(\dfrac{y^2}{2}\) \(=\displaystyle \dfrac{1}{2} \int(-2 x) e^{-x^2}\, d x\)
\(y^2\) \(=e^{-x^2}+c\)

 
\(\text{Given the solution passes through}\ (0,1):\)

\(1^2=e^0+c \ \ \Rightarrow \ \ c=0\)

\(y^2=e^{-x^2}\)

\(y=\left(e^{-x^2}\right)^{\tfrac{1}{2}}=e^{-\tfrac{x^2}{2}}\)

Filed Under: Equations and Slope Fields Tagged With: Band 5, smc-7296-20-Differential Equations, smc-7296-30-\(\dfrac{dy}{dx}=f(x y)\)

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