If point \(P\) lies on the unit circle at coordinates \((0.5, -0.866)\), which quadrant does \(P\) lie in and what is the approximate angle in standard position?
- Quadrant \(\text{III}\), 210\(^{\circ}\)
- Quadrant \(\text{IV}\), 300\(^{\circ}\)
- Quadrant \(\text{III}\), 240\(^{\circ}\)
- Quadrant \(\text{IV}\), 330\(^{\circ}\)
Show Worked Solution
\(P\ \text{is found in Quadrant IV}\)
\(\theta = 60^{\circ}\)
\(\text{Angle in standard position}\ =360-60 = 300^{\circ}\)
\(\Rightarrow B\)