Circles and Hyperbolas, SMB-011 Find the centre and radius of the circle with the equation `x^2-12x + y^2 + 2y-12 = 0` (2 marks) Show Answers Only `text(Centre)\ (6, −1)` `text(Radius = 7)` Show Worked Solution `x^2-12x + y^2 + 2y-12` `= 0` `(x-6)^2 + (y + 1)^2-36-1-12` `= 0` `(x-6)^2 + (y + 1)^2` `= 49` `:.\ text(Centre)\ (6, −1)` `:.\ text(Radius = 7)`