- Find the centre and radius of the circle with the equation
- `x^2+6x+y^2+4y+4=0` (2 marks)
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- Sketch the circle on the graph below. (1 mark)
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Show Answers Only
a. `(x+3)^2 + (y+2)^2 = 3^2`
`:.\ text(Centre:)\ (-3,-2)\text(, Radius:)\ 3`
b.
Show Worked Solution
| a. | `x^2+6x+y^2+4y+4` | `=0` |
| `x^2+6x+9+y^2+4y+4-9` | `=0` | |
| `(x+3)^2+(y+2)^2` | `=3^2` |
`:.\ text(Centre:)\ (-3,-2)\text(, Radius:)\ 3`
b.