Circles and Hyperbolas, SMB-019 Find the centre and radius of the circle with the equation `x^2+6x+y^2-y+3=0` (2 marks) Show Answers Only `text{Centre}\ (-3,1/2),\ text{Radius}\ = 5/2` Show Worked Solution `x^2+6x+y^2-y+3` `=0` `x^2+6x+9+y^2-y+1/4-25/4` `=0` `(x+3)^2+(y-1/2)^2` `=25/4` `(x+3)^2+(y-1/2)^2` `=(5/2)^2` `text{Centre}\ (-3,1/2),\ text{Radius}\ = 5/2`