Congruency, SMB-003

In the figure below, the line \(AD\) intersects \(BE\) at \(C\), \(BC = CD\) and \(AC = EC\).

Prove that this pair of triangles are congruent. (2 marks)

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\( \angle BCE = \angle DCE\ \ \text{(vertically opposite)} \)

\(BC = CD\ \ \text{(given)} \)

\(AC = EC\ \ \text{(given)} \)

\(\therefore\ \Delta ABC \equiv \Delta EDC\ \ \text{(SAS)}\)