In the figure below, \(ABCD\) is a parallelogram where opposite sides of the quadrilateral are equal.
Prove that a diagonal of the parallelogram produces two triangles that are congruent. (2 marks)
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\(\text{One of multiple solutions:}\)
\( AB=CD\ \ \text{and}\ \ AC=BD\ \ \text{(given)} \)
\(BC\ \text{is common} \)
\(\therefore\ \Delta ABC \equiv \Delta DCB\ \ \text{(SSS)}\)