Divide quadrilateral \(ABCD\) into triangles and using the angle sum of one triangle, determine the sum of the internal angles of a quadrilateral. (2 marks)
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\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)
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\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)