Quadratics, SMB-010 Factorise `y=6-x-x^2` (2 marks) --- 4 WORK AREA LINES (style=lined) --- Find the vertex of the parabola with equation `y=6-x-x^2` (2 marks) --- 5 WORK AREA LINES (style=lined) --- Show Answers Only `y=(2-x)(x+3)` `text{Vertex}\ = (-1/2,6 1/4)` Show Worked Solution i. `y` `=6-x-x^2` `=-(x^2+x-6)` `=-(x-2)(x+2)` `=(2-x)(x+3)` ii. `text{Solutions at}\ \ x=2,-3.` `text{Line of symmetry at mid-point of solutions.}` `x=(2+(-3))/2=-1/2` `text{Substitute}\ \ x=-1/2\ \ text{into}\ \ y=6-x-x^2` `y=6+1/2-1/4=6 1/4` `:.\ text{Vertex}\ = (-1/2,6 1/4)`