Quadratics, SMB-011 Factorise `y=2x^2+5x-3` (1 mark) --- 2 WORK AREA LINES (style=lined) --- Find the vertex of the parabola with equation `y=2x^2+5x-3` (2 marks) --- 4 WORK AREA LINES (style=lined) --- Show Answers Only `y=(2x-1)(x+3)` `text{Vertex}\ = (-5/4,-49/8)` Show Worked Solution i. `y` `=2x^2+5x-3` `=(2x-1)(x+3)` ii. `text{Solutions at}\ \ x=1/2,-3.` `text{Line of symmetry at mid-point of solutions.}` `x=(1/2+(-3))/2=-5/4` `text{Substitute}\ \ x=-5/4\ \ text{into}\ \ y=2x^2+5x-3` `y=2xx(-5/4)^2-5xx5/4-3=-49/8` `:.\ text{Vertex}\ = (-5/4,-49/8)`