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Similarity, SMB-019

Prove that this pair of triangles are similar.   (2 marks)
 

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\(\text{Proof (See Worked Solution)}\)

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\(\dfrac{AB}{GH} = \dfrac{11}{22} = \dfrac{1}{2} \)

\(\dfrac{BC}{FG} = \dfrac{3.5}{7} = \dfrac{1}{2} \)

\(\angle ABC = \angle FGH = 95^{\circ} \ \ \text{(given)} \)
 

\(\therefore \Delta ABC\ \text{|||}\ \Delta HGF\ \ \text{(sides adjacent to equal angles in proportion)}\)

Filed Under: Similarity Tagged With: num-title-ct-pathc, smc-4746-35-Similarity proofs

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