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Similarity, SMB-022

Prove that this pair of triangles are similar.   (2 marks)

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\(\text{Proof (See Worked Solution)}\)

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\(\angle PQT = \angle SQR \ \text{(vertically opposite)} \)

\(\dfrac{PQ}{QS} = \dfrac{2.5}{5} = \dfrac{1}{2} \)

\(\dfrac{TQ}{QR} = \dfrac{2}{4} = \dfrac{1}{2} \)

\(\therefore \Delta PQT\ \text{|||}\ \Delta SQR\ \ \text{(sides adjacent to equal angles in proportion)}\)

Filed Under: Similarity Tagged With: num-title-ct-pathc, smc-4746-35-Similarity proofs

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