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Calculus, 2ADV C1 EQ-Bank 7

Differentiate  `x(1+3x)^5`  with respect to `x`.   (2 marks)

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`y^{′}=(1+3x)^4(18 x+1)`

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`y=x(1+3x)^5`

`text{Using the product and chain rules:}`

`y^{′}` `=1 xx (1+3x)^5+15x(1+3x)^4`  
  `=(1+3x)^4(1+3x+15 x)`  
  `=(1+3x)^4(18 x+1)`