In the interval \(-\pi \leq x \leq \pi\), the graph of \(y=a+\sec (x)\), where \(a \in R\), has two \(x\)-intercepts when
- \(0 \leq a \leq 1\)
- \(-1<a<1\)
- \(a \leq-1\) or \(a>1\)
- \(-1 \leq a<0\)
- \(a<-1\) or \(a \geq 1\)
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In the interval \(-\pi \leq x \leq \pi\), the graph of \(y=a+\sec (x)\), where \(a \in R\), has two \(x\)-intercepts when
\(E\)
\(\text{Sketch}\ \ y=\sec(x)\ \ \text{for}\ \ -\pi \leq x \leq \pi \)
\(\text{Translate vertically to test for values of}\ a\ \text{that satisfy}\)
\(\text{two intercepts on the}\ x\text{-axis.}\)
\(a \geq 1\ \ \text{or}\ \ a \lt -1\)
\(\Rightarrow E\)
Let `f(x) = text(cosec) (x)`. The graph of `f` is transformed by:
The rule of the transformed graph is
`B`
`f_1 (x) = 3\ text(cosec) (x)`
`f_2 (x) = 3\ text(cosec) (x – 1)`
`f_3 (x) = g(x) = 3\ text(cosec) (2x – 1)`
`=> B`