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Calculus, SPEC1-NHT 2019 VCAA 6

Part of the graph of  `y = (2)/(sqrt(x^2-4x+3))`, where  `x > 3`, is shown below.
 


 

Find the volume of the solid of revolution formed when the graph of  `y = (2)/(sqrt(x^2-4x+3))`  from  `x = 4`  to  `x = 6`  is rotated about the `x`-axis. Give your answer in the form  `a log_e(b)`  where `a` and `b` are real numbers.   (5 marks)

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`pi log_e ((9)/(5))`

Show Worked Solution

`V = pi int_4 ^6 (4)/(x^2 – 4x + 3)\ dx`
 

`text(Using partial fractions:)`

`(4)/(x^2 – 4x + 3) = (a)/((x-3)) + (b)/((x-1))`

`a(x -1) + b(x – 3)= 4`
 

`text(When)\ \ x = 1, \ -2b = 4  => \ b = -2`

`text(When)\ \ x = 3, \ 2a = 4  => \ a = 2`

`:. \ V` `= pi int_4 ^6 (2)/(x-3) – (2)/(x-1)\ dx`
  `= 2 pi [log_e(x-3) -log_e(x-1)]_4 ^6`
  `= 2 pi [log_e 3 – log_e 5 – (log_e 1 – log_e3)]`
  `= 2 pi (2log_e 3 – log_e 5)`
  `= 2pi log_e((9)/(5))`

Filed Under: Solids of Revolution Tagged With: Band 4, smc-1180-40-Other graphs, smc-1180-50-x-axis rotations, smc-1180-70-Partial Fractions

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