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Ratio, SM-Bank 040

Paul stacks milk cartons into supermarket refrigerator shelves.

Each shelf is stacked with 6 full cream milk cartons, 4 lite milk cartons and 2 skim milk cartons.

Every hour Paul stacks 240 milk cartons in total.

How many lite milk cartons does he stack every hour?  (2 marks)

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\(80\)

Show Worked Solution

\(\text{Total Cartons per shelf}=6+4+2=12\)
  

\(\text{Fraction of lite}=\dfrac{4}{12}=\dfrac{1}{3}\)

\(\text{Total lite per hour}=\dfrac{1}{3}\times 240=80\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 037 MC

Tony is making a fruit cake.

The recipe says he needs 3 cups of sultanas for every 5 cups of flour.

If 2.5 cups of flour are used, how many cups of sultanas are needed?
 

  1. \(0.5\ \text{cups}\)
  2. \(1.5\ \text{cups}\)
  3. \(2.5\ \text{cups}\)
  4. \(4.5\ \text{cups}\)
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Strategy 1:}\)

\(2.5\ \text{ is half of }\ 5\ \text{cups of flour, therefore half of}\)

\(3\ \text{cups of sultanas is required.}\)

\(\rightarrow\ 1.5\text{ cups of sultanas needed.}\)

 

\(\text{Strategy 2:}\)

\(\text{Let}\ \ n = \text{cups of sultanas needed}\)

\(\dfrac{n}{2.5}\) \(=\dfrac{3}{5}\)
\(\therefore \ n\) \(=\dfrac{3\times 2.5}{5}\)
  \(=1.5\ \text{cups}\)

 
\(\Rightarrow\ B\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 036

Milly is using this cupcake recipe.
 

 How many cups of sugar are needed for 20 cupcakes?  (2 marks)

Show Answers Only

\(3\dfrac{3}{4}\ \text{cups}\)

Show Worked Solution

\(\text{From the recipe:}\)

\(\dfrac{3}{4}\ \text{cups} = 4\ \text{cupcakes}\)

\(\therefore\ \text{Sugar in 20 cupcakes}\) \(=\dfrac{3}{4}\times 5\)
  \(=\dfrac{15}{4}\)
  \(=3\dfrac{3}{4}\ \text{cups}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 031

Jordan has 4 times as many blue pencils as black pencils.

Altogether he has 90 pencils.

How many blue pencils does he have?  (2 marks)

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\(72\ \text{blue pencils}\)

Show Worked Solution

\(\text{Method 1}\)

\(\text{Ratio of blue to black}=4:1\)

\(\text{Total parts}=4+1=5\)
  

\(\text{Fraction blue}=\dfrac{4}{5}\)

\(\text{Number of blue pencils}=\dfrac{4}{5}\times 90=72\)
  

\(\text{Method 2 (Advanced)}\)

\(\text{Let}\ \ x = \text{the number of black pencils}\)

\(\text{Then the number of blue pencils}=4x\)

\(\text{Total pencils }= x + 4x\) \(=5x\)
\(\rightarrow\ 5x\) \(= 90\)
\(x\) \(=\dfrac{90}{5}= 18\)

 

\(\therefore \ \text{The number of blue pencils}\)

\(=90-18= 72\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 030 MC

A school has 360 students.

The ratio of boys to girls is 4 to 6.

How many boys attend the school?

  1. \(90\)
  2. \(144\)
  3. \(216\)
  4. \(240\)
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Total students}=4+6=10\)
 

\(\text{Fraction of boys}=\dfrac{4}{10}=\dfrac{2}{5}\)

\(\text{Boys}=\dfrac{2}{5}\times 360=144\)
  

\(\Rightarrow B\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 028 MC

A little athletics club is established in a town.

In the first week, 5 girls and 6 boys joined the club.

In the second week, another 4 boys and some more girls joined the club.

The number of girls in the club was now double the number of boys.

How many girls joined the club in the second week?

  1. \(7\)
  2. \(15\)
  3. \(17\)
  4. \(20\)
Show Answers Only

\(B\)

Show Worked Solution

\(\text{1st week}\rightarrow 6\ \text{boys.}\)

\(\text{2nd week }\rightarrow 6+4 = 10\ \text{boys.}\)

\(\text{Total girls in 2nd week.}\)

\(= 2\times 10\)

\(= 20\)
 

\(\therefore\ \text{Girls joining in 2nd week.}\)

\(= 20-5\)

\(= 15\)
 

\(\Rightarrow B\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 027 MC

Muriel made a batch of cookies.
 

 
Each cookie had 4 chocolate chips and 3 jelly snakes on it.

Muriel used 39 jelly snakes in the batch of cookies.

How many chocolate chips did she use?

  1. \(13\)
  2. \(26\)
  3. \(52\)
  4. \(78\)
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\(C\)

Show Worked Solution

\(\text{Number of cookies made}\)

\(=\dfrac{39}{3}\)

\(=13\)

\(\therefore\ \text{Chocolate chips used}\)

\(=13\times 4\)

\(=52\)

 
\(\Rightarrow C\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 025

The ratio of the angles in a triangle is 1:2:5.

Calculate the sizes of all three angles?  (2 marks)

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\(22.5^{\circ}, 45^{\circ} \text{ and}\ 112.5^{\circ}\)

Show Worked Solution

\(\text{Total parts}=1+2+5=8\ \text{and the angle sum of a triangle}=180^{\circ}\)

\(\dfrac{1}{8}\times 180\) \(=22.5\)
\(\dfrac{2}{8}\times 180\) \(=45\)
\(\dfrac{5}{8}\times 180\) \(=112.5\)

    
\(\therefore\ \text{The angles in the triangle are }22.5^{\circ}, 45^{\circ} \text{ and}\ 112.5^{\circ}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 022

Divide $420 in the ratio 1:3:2.  (2 marks)

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\($70, $210 \text{ and } $140\)

Show Worked Solution

\(\text{Total number of parts}=1+3+2=6\)

\(\dfrac{1}{6}\times 420\) \(=70\)
\(\dfrac{3}{6}\times 420\) \(=210\)
\(\dfrac{2}{6}\times 420\) \(=140\)

  
\(\therefore\ $420\ \text{divided in the ratio }\ 1:3:2\ \text{ is }\ $70, $210\ \text{and } $140.\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 021

Divide 84 days in the ratio 3:4.  (2 marks)

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\(36\ \text{days and } 48\ \text{days}\)

Show Worked Solution

\(\text{Total number of parts}=3+4=7\)

\(\dfrac{3}{7}\times 84\) \(=36\)
\(\dfrac{4}{7}\times 84\) \(=48\)

  
\(\therefore\ 84\ \text{days divided in the ratio }3:4\ \text{is }36\ \text{days and } 48\ \text{days.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 020

Divide 480 tonnes in the ratio 1:5.  (2 marks)

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\(80\ \text{tonnes and}\ 400\ \text{tonnes}\)

Show Worked Solution

\(\text{Total number of parts}=1+5=6\)

\(\dfrac{1}{6}\times 480\) \(=80\)
\(\dfrac{5}{6}\times 480\) \(=400\)

  
\(\therefore\ 480\ \text{tonnes divided in the ratio }1:5\ \text{is }80\ \text{tonnes and } 400\ \text{tonnes.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 019

Divide $130 in the ratio 5:8.  (2 marks)

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\($50\ \text{and}\ $80\)

Show Worked Solution

\(\text{Total number of parts}=5+8=13\)

\(\dfrac{5}{13}\times 130\) \(=50\)
\(\dfrac{8}{13}\times 130\) \(=80\)

  
\(\therefore\ \$130\ \text{divided in the ratio }5:8\ \text{is }$50\ \text{and}\ $80.\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 018

The ratio of kilograms of bananas to apples at the fruit shop is \(11:5\).

  1. What fraction of the fruit is bananas?  (1 mark)

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  2. If there are 128 kilograms of bananas and apples altogether, how many kilograms of bananas are there?  (2 marks)

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a.    \(\dfrac{11}{16}\)

b.    \(88\ \text{kg of bananas}\)

Show Worked Solution

a.    \(\text{Total fruits}=11+5=16\)

\(\text{Fraction bananas}=\dfrac{11}{16}\)
 

b.   
\(\text{Kilograms of bananas}\) \(=\dfrac{11}{16}\times 128\)
    \(=88\)

 
\(\therefore\ \text{There are }88\ \text{kgs of bananas.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

Ratio, SM-Bank 017

The ratio of dogs to cats in an animal rescue shelter is \(5:4\).

  1. What fraction of the animals are dogs?  (1 mark)

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  2. What fraction of the animals are cats?  (1 mark)

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  3. If there are 36 animals in the shelter, how many are dogs?  (2 marks)

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a.    \(\dfrac{5}{9}\)

b.    \(\dfrac{4}{9}\)

c.    \(20\ \text{dogs}\)

Show Worked Solution

a.    \(\text{Total animals}=5+4=9\)

\(\text{Fraction dogs}=\dfrac{5}{9}\)
 

b.    \(\text{Fraction cats}=\dfrac{4}{9}\)

 

c.   
\(\text{Number of dogs}\) \(=\dfrac{5}{9}\times 36\)
    \(=20\)

 
\(\therefore\ \text{There are }20\ \text{dogs in the shelter.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio

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