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Ratio, SM-Bank 041 MC

An ancient coin is made up of gold and silver in the ratio 1:3.

The coin weighs 21.65 grams.

How many grams of silver are in the ancient coin?

  1. \(5.4125\)
  2. \(7.217\)
  3. \(14.433\)
  4. \(16.2375\)
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\(D\)

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\(\text{Total parts}=1+3=4\) 
  

\(\text{Fraction of silver}=\dfrac{3}{4}\)

\(\text{Silver}=\dfrac{3}{4}\times 21.65=16.2375\)
  

\(\Rightarrow D\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 038

Damon buys 25 kilograms of salt for his pool for $33.75.

The salt can be purchased in 1 kilogram bags.

How much does 9 kilograms of salt cost?  (2 marks)

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\($12.15\)

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\(\text{C}\text{ost of 1 kilogram}\)

\(=\dfrac{33.75}{25}\)

\(= $1.35\)
 

\(\therefore\ \text{C}\text{ost of 9 kilograms}\)

\(= 9\times 1.35\)

\(= $12.15\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 032 MC

Shelley and Carly collect dolls.

The ratio of the number of dolls Shelley owns compared to Carly is  3 : 2.

Shelley owns 12 dolls.

How many dolls does Carly own?

  1. \(2\)
  2. \(6\)
  3. \(8\)
  4. \(18\)
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\(C\)

Show Worked Solution

\(\text{Shelley’s dolls represents 3 parts}\)

\(3\ \text{parts}\) \(=12\)
\(1\ \text{part}\) \(=\dfrac{12}{3}=4\)

    
\(\text{Carly’s dolls represents 2 parts}\)

\(=2\times 4=8\)
 

\(\therefore\ \text{There Carly owns}\ 8\ \text{dolls.}\)
 

\(\Rightarrow C\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 031

Jordan has 4 times as many blue pencils as black pencils.

Altogether he has 90 pencils.

How many blue pencils does he have?  (2 marks)

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\(72\ \text{blue pencils}\)

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\(\text{Method 1}\)

\(\text{Ratio of blue to black}=4:1\)

\(\text{Total parts}=4+1=5\)
  

\(\text{Fraction blue}=\dfrac{4}{5}\)

\(\text{Number of blue pencils}=\dfrac{4}{5}\times 90=72\)
  

\(\text{Method 2 (Advanced)}\)

\(\text{Let}\ \ x = \text{the number of black pencils}\)

\(\text{Then the number of blue pencils}=4x\)

\(\text{Total pencils }= x + 4x\) \(=5x\)
\(\rightarrow\ 5x\) \(= 90\)
\(x\) \(=\dfrac{90}{5}= 18\)

 

\(\therefore \ \text{The number of blue pencils}\)

\(=90-18= 72\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-25-Dividing in a given ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 026

It is known that one of the angles in a triangle is \(120^{\circ}\).

Calculate the size of the other 2 angles if they are in the ratio \(2:3\).  (3 marks)

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\(24^{\circ}\ \text{and}\ 36^{\circ}\)

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\(\text{Angle sum of a triangle}=180^{\circ}\)

\(\therefore\ \text{Remaining angles}=180-120=60^{\circ}\)

\(\text{Total parts remaining angles}=2+3=5\)    

\(\text{1st angle}=\dfrac{2}{5}\times 60=24\)

\(\text{2nd angle}=\dfrac{3}{5}\times 60=36\)
    

\(\therefore\ \text{The remaining angles are}\ 24^{\circ}\ \text{and}\ 36^{\circ}.\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 024

Joe and Andrew are cleaning fish. For every 4 fish that Joe cleans, Andrew cleans 7.

If Joe cleaned 36 fish, how many did Andrew clean?  (2 marks)

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\(63 \text{ fish}\)

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\(\text{Joe’s cleaned fish represents 4 parts}\)

\(4\ \text{parts}\) \(=36\)
\(1\ \text{part}\) \(=\dfrac{36}{4}=9\)

    
\(\text{Andrew’s cleaned fish represents 7 parts}\)

\(=9\times 7=63\)
 

\(\therefore\ \text{Andrew cleaned}\ 63\ \text{fish.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

Ratio, SM-Bank 023

This year there are 108 students in Year 8 and the ratio of Year 7 students to Year 8 students is 8:9.

Use this information to calculate the number of students in Year 7 this year.  (2 marks)

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\(96 \text{ students in Year 7}\)

Show Worked Solution

\(\text{Year 8 represents 9 parts}\)

\(9\ \text{parts}\) \(=108\)
\(1\ \text{part}\) \(=\dfrac{108}{9}=12\)

    
\(\text{Year 7 represents 8 parts}\)

\(=12\times 8=96\)
 

\(\therefore\ \text{There are}\ 96\ \text{students in Year 7.}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-30-Unitary method ratio

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