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Solving Problems, SM-Bank 020

In the diagram below, \(QR\) is parallel to \(SU\).
  

Find the value of \(x^{\circ}\), giving reasons for your answer.   (2 marks)

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\(\angle STP = 38^{\circ}\ \ \text{(corresponding angles)}\)

\((x+30)^{\circ}\) \(=180-38\ \ \text{(180° in straight line)} \)  
\(x^{\circ}\) \(=142-30\)  
  \(=112^{\circ}\)  
Show Worked Solution

\(\angle STP = 38^{\circ}\ \ \text{(corresponding angles)}\)

\((x+30)^{\circ}\) \(=180-38\ \ \text{(180° in straight line)} \)  
\(x^{\circ}\) \(=142-30\)  
  \(=112^{\circ}\)  

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-50-Supplementary

Solving Problems, SM-Bank 011

In the diagram below, \(QR\) is parallel to lines \(SU\) and \(VW\).
 

Find the value of \(x^{\circ}\), giving reasons for your answer.   (3 marks)

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\(\angle UTQ = 125^{\circ}\ \ \text{(corresponding angles)} \)

\(\angle STX=125^{\circ}\ \ \text{(vertically opposite angles)}\)

\(x^{\circ} = 180-125=55^{\circ} \ \ \text{(cointerior angles)}\)

Show Worked Solution

\(\angle UTQ = 125^{\circ}\ \ \text{(corresponding angles)} \)

\(\angle STX=125^{\circ}\ \ \text{(vertically opposite angles)}\)

\(x^{\circ} = 180-125=55^{\circ} \ \ \text{(cointerior angles)}\)

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-25-Cointerior, smc-492640-Vertically opposite

Solving Problems, SM-Bank 010

In the diagram below, \(BC\) is parallel to \(DE\) and \(\angle ACB\) is a right-angle.
 

Find the value of \(x^{\circ}\), giving reasons for your answer.   (3 marks)

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\(\text{Extend line}\ BC: \)
 

\(\angle GCF=180-120=60^{\circ}\ \ \text{(180° in a straight line)}\)

\(x^{\circ} = 60^{\circ} \ \ \text{(corresponding angles)}\)

Show Worked Solution

\(\text{Extend line}\ BC: \)
 

\(\angle GCF=180-120=60^{\circ}\ \ \text{(180° in a straight line)}\)

\(x^{\circ} = 60^{\circ} \ \ \text{(corresponding angles)}\)

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-50-Supplementary, smc-4926-70-Add parallel line

Solving Problems, SM-Bank 009

In the diagram below, two parallel lines \(OB\) and \(DC\) cut the horizontal transversal \(OE\), and \(OA\) is perpendicular to \(OE\).
 

Find the value of \(a^{\circ}\), giving reasons for your answer.   (2 marks)

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\(\angle BOE=90-20=70^{\circ}\ \ \text{(complementary angles)}\)

\(a^{\circ} = 70^{\circ} \ \ \text{(corresponding angles)}\)

Show Worked Solution

\(\angle BOE=90-20=70^{\circ}\ \ \text{(complementary angles)}\)

\(a^{\circ} = 70^{\circ} \ \ \text{(corresponding angles)}\)

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-55-Complementary

Solving Problems, SM-Bank 027

Find the value of \(x^{\circ}\) in the diagram, giving reasons for your answer.   (2 marks)
 

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\(45°\)

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\(\text{Angle above}\ \angle (3x)^{\circ} = (180-3x)^{\circ}\ \ \text{(180° in a straight line)}\)

\(180-3x\) \(=x\ \ \text{(corresponding angles)} \)  
\(4x\) \(=180\)  
\(x^{\circ}\) \(=\dfrac{180}{4}\)  
  \(=45^{\circ}\)  

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-50-Supplementary

Solving Problems, SM-Bank 024

Find the value of \(x\) in the diagram, giving reasons for your answer.   (2 marks)
 

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\(113°\)

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\(\text{Supplementary angles sum to 180°}\ (180-82 = 98^{\circ}) \)

\(x-15\) \(=98\ \ \text{(corresponding angles)}\)  
\(x^{\circ}\) \(=98+15\)  
  \(=113^{\circ}\)  

Filed Under: Solving Problems Tagged With: num-title-ct-core, smc-4926-10-Corresponding, smc-4926-50-Supplementary

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