Determine the value of \(x^{\circ}\) in the quadrilateral above, giving reasons for your answer. (2 marks)
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Determine the value of \(x^{\circ}\) in the quadrilateral above, giving reasons for your answer. (2 marks)
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\(30^{\circ}\)
\(\text{Angle sum of quadrilaterals = 360°:} \)
\(360\) | \(=2x + 3x + 4x + 2x \) | |
\(12x^{\circ}\) | \(=360\) | |
\(x^{\circ}\) | \(=\dfrac{360}{12}\) | |
\(=30^{\circ}\) |
Determine the value of the two unknown angles in the quadrilateral above, giving reasons for your answer. (3 marks)
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\(\text{Angle sum of quadrilaterals = 360°:} \)
\(360\) | \(=5x+3x+79+105 \) | |
\(8x\) | \(=360-184\) | |
\(x^{\circ}\) | \(=\dfrac{176}{8}\) | |
\(=22^{\circ}\) |
\(\text{Unknown angle 1}\ = 3 \times 22 = 66^{\circ}\)
\(\text{Unknown angle 2}\ = 5 \times 22 = 110^{\circ}\)
\(\text{Angle sum of quadrilaterals = 360°:} \)
\(360\) | \(=5x+3x+79+105 \) | |
\(8x\) | \(=360-184\) | |
\(x^{\circ}\) | \(=\dfrac{176}{8}\) | |
\(=22^{\circ}\) |
\(\text{Unknown angle 1}\ = 3 \times 22 = 66^{\circ}\)
\(\text{Unknown angle 2}\ = 5 \times 22 = 110^{\circ}\)
Find the value of \(a^{\circ}\) in the diagram below. (2 marks)
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\(132^{\circ}\)
\(\text{Since there are 360° in a quadrilateral:}\)
\(360\) | \(=a+62+85+81\) | |
\(360\) | \(=a+228\) | |
\(a^{\circ}\) | \(=360-228\) | |
\(=132^{\circ}\) |
Find the value of \(x^{\circ}\) in the diagram below. (2 marks)
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\(81^{\circ}\)
\(\text{Since there are 360° in a quadrilateral:}\)
\(360\) | \(=x+98+108+73\) | |
\(360\) | \(=x+279\) | |
\(x^{\circ}\) | \(=360-279\) | |
\(=81^{\circ}\) |
Find the value of \(a^{\circ}\) in the diagram below. (2 marks)
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\(60^{\circ}\)
\(\angle BCD\ \text{(reflex)} = 360-130=230^{\circ}\)
\(\text{Since there are 360° in a quadrilateral:}\)
\(360\) | \(=a+40+230+30\) | |
\(360\) | \(=a+300\) | |
\(a^{\circ}\) | \(=360-300\) | |
\(=60^{\circ}\) |
Find the value of \(x^{\circ}\) in the diagram below. (2 marks)
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\(110^{\circ}\)
\(\text{Since there are 360° in a quadrilateral:}\)
\(360\) | \(=x+55+105+90\) | |
\(360\) | \(=x+250\) | |
\(x^{\circ}\) | \(=360-250\) | |
\(=110^{\circ}\) |
Divide quadrilateral \(ABCD\) into triangles and using the angle sum of one triangle, determine the sum of the internal angles of a quadrilateral. (2 marks)
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\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)
\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)
Divide quadrilateral \(ABCD\) into triangles and using the angle sum of one triangle, determine the sum of the internal angles of a quadrilateral. (2 marks)
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\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)
\(ABCD\ \text{can be divided into 2 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCD = 2 \times 180^{\circ} = 360^{\circ}\)