\(ABCDE\) is a pentagon.
- Using point \(A\) as one vertex, divide the pentagon into the maximum number of triangles possible. (1 mark)
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- Using the angle sum of one triangle, show that the sum of the internal angles of the pentagon is 540°. (2 marks)
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Show Answers Only
i.
ii. \(ABCDE\ \text{can be divided into 3 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCDE = 3 \times 180^{\circ} = 540^{\circ}\)
Show Worked Solution
i.
ii. \(ABCDE\ \text{can be divided into 3 triangles.}\)
\(\text{Angle sum of a triangle = 180°}\)
\(\text{Angle sum of}\ ABCDE = 3 \times 180^{\circ} = 540^{\circ}\)