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CORE, FUR1 2016 VCAA 4-5 MC

The weights of male players in a basketball competition are approximately normally distributed with a mean of 78.6 kg and a standard deviation of 9.3 kg.

Part 1

There are 456 male players in the competition.

The expected number of male players in the competition with weights above 60 kg is closest to

  1.     `3`
  2.   `11`
  3.   `23`
  4. `433`
  5. `445`

 

Part 2

Brett and Sanjeeva both play in the basketball competition.

When the weights of all players in the competition are considered, Brett has a standardised weight of  `z` = – 0.96 and Sanjeeva has a standardised weight of  `z` = – 0.26

Which one of the following statements is not true?

  1. Brett and Sanjeeva are both below the mean weight for players in the basketball competition.
  2. Sanjeeva weighs more than Brett.
  3. If Sanjeeva increases his weight by 2 kg, he would be above the mean weight for players in the basketball competition.
  4. Brett weighs more than 68 kg.
  5. More than 50% of the players in the basketball competition weigh more than Sanjeeva 
Show Answers Only

`text(Part 1:)\ E`

`text(Part 2:)\ C`

Show Worked Solution

`text(Part 1)`

`text(Find)\ ztext(-score of 60 kg)`

`ztext(-score)` `= (x – barx)/s`
  `= (60 – 78.6)/9.3`
  `= −2`

 

 

`text(Players with weight above 60 kg)`

`= 97.5text(%) xx 456`

`= 445`

`=> E`

 

`text(Part 2)`

`text(Calculate the weight of each player:)`

`text(Brett)`

`−0.96` `= (x – 78.6)/9.3`
`x` `= (9.3 xx −0.96) + 78.6`
  `~~ 69.7\ text(kg)`

 
`text(Sanjeev)`

`−0.26` `= (x – 78.6)/9.3`
`x` `= (9.3 xx −0.26) + 78.6`
  `~~ 76.2\ text(kg)`

 
`text(Consider)\ C,`

`76.182 + 2 = 78.182 < 78.6`

`:. C\ text(is not true.)`

`=> C`

Filed Under: Normal Distribution Tagged With: Band 4, smc-600-10-Single z-score, smc-600-30-Comparing Data / Data Sets

CORE, FUR1 2012 VCAA 4 MC

A class of students sat for a Biology test and a Legal Studies test. Each test had a possible maximum score of 100 marks. The table below shows the mean and standard deviation of the marks obtained in these tests.
 


 

The class marks in each subject are approximately normally distributed.

Sashi obtained a mark of 81 in the Biology test.

The mark that Sashi would need to obtain on the Legal Studies test to achieve the same standard score for both Legal Studies and Biology is

A.   81

B.   82

C.   83

D.   87

E.   95

Show Answers Only

`D`

Show Worked Solution
`z text {-score (Biology)}` `= ( x – bar x)/ s`
  `= (81-54)/15`
  `= 1.8`

 

`text(Legal Studies mark must have a) \ z text(-score of 1.8:)`

`1.8` `= (x-78)/5`
`9`  `= x – 78`
`x` `= 87`

 
`rArr D`

Filed Under: Normal Distribution Tagged With: Band 4, smc-600-30-Comparing Data / Data Sets

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