Let `f : R to R, \ f(x) = (2x - 1)(2x + 1)(3x - 1)` and `g : (–∞, 0) to R, \ g(x) = x log_e(–x)`.
The maximum number of solutions for the equation `f(x - k) = g(x)`, where `k ∈ R`, is
- 0
- 1
- 2
- 3
- 4
Show Worked Solution
`text{By CAS, graph}`
♦ Mean mark 39%.
`f(x) = (2x – 1)(2x + 1)(3x – 1) , text{and}`
`g(x) = x log_e (-x) , x < 0`
`text{If} \ f(x) \ text{is translated to the left, by inspection,}`
`text{a maximum of 3 intersections can occur.}`
`=> \ D`