Trigonometry, SMB-053 Find the value of \(x\), correct to 1 decimal place. (2 marks) Show Answers Only \(x=8.0\ \text{cm}\) Show Worked Solution \(\dfrac{x}{\sin42^{\circ}}\) \(=\dfrac{12}{\sin 86^{\circ}}\) \(x\) \(=\dfrac{12 \times \sin 42^{\circ}}{\sin 86^{\circ}}\) \(=8.049…\) \(=8.0\ \text{cm (to 1 d.p.)}\)