Trigonometry, SMB-056 Find \(\theta\), to the nearest degree, such that \(\dfrac{12}{\sin \theta} = \dfrac{15}{\sin 26^{\circ}} \) (2 marks) Show Answers Only \(\theta=21^{\circ}\) Show Worked Solution \(\dfrac{12}{\sin \theta}\) \(= \dfrac{15}{\sin 26^{\circ}} \) \(\dfrac{\sin \theta}{12}\) \(= \dfrac{\sin 26^{\circ}}{15} \) \(\sin \theta\) \(= \dfrac{12 \times \sin 26^{\circ}}{15}\) \(\theta\) \(=\sin^{-1} (0.3507) \) \(=21^{\circ}\ \text{(nearest degree)} \)