Trigonometry, SMB-060 Find the value of \(\alpha\), correct to the nearest degree. (2 marks) Show Answers Only \(\alpha=39^{\circ}\) Show Worked Solution \(\dfrac{\sin \alpha}{9}\) \(= \dfrac{\sin 79^{\circ}}{14} \) \(\sin \alpha\) \(= \dfrac{9 \times \sin 79^{\circ}}{14}\) \(\alpha\) \(=\sin^{-1} (0.6310) \) \(=39.12…^{\circ} \) \(=39^{\circ}\ \text{(nearest degree)} \)
