Trigonometry, SMB-066 Find the value of \(\theta\), correct to the nearest degree. (2 marks) --- 5 WORK AREA LINES (style=lined) --- Show Answers Only \(\theta=35^{\circ}\) Show Worked Solution \(\cos A\) \(= \dfrac{b^2+c^2-a^2}{2bc} \) \(\cos \theta\) \(= \dfrac{16.2^2+18.1^2-10.5^2}{2 \times 16.2 \times 18.1}\) \(= 0.818…\) \(\therefore \theta\) \(= \cos^{-1} (0.818…) \) \(=35.09…^{\circ} \) \(=35^{\circ}\ \ \text{(nearest degree)} \)