Trigonometry, SMC-051 Solve for \(b\), giving your answer correct to 1 decimal place. \(\dfrac{b}{\sin 22^{\circ}} = \dfrac{17}{\sin 67^{\circ}}\) (2 marks) Show Answers Only \(b=6.9\) Show Worked Solution \(\dfrac{b}{\sin 22^{\circ}}\) \(= \dfrac{17}{\sin 67^{\circ}}\) \(b\) \(=\dfrac{17 \times \sin 22^{\circ}}{\sin 67^{\circ}}\) \(=6.9\ \text{(to 1 d.p.)}\)