Algebra, STD1 EQ-Bank 6 MC

An AFL football team scored 15 times in a game, made up of goals and behinds.

Goals are worth 6 points and behinds are worth 1 point. The team's total score was 45 points.

Let  \(g\) = number of goals and  \(b\) = number of behinds.

Which pair of equations correctly represents this situation?

1. \(g+b=45\)  and  \(6g+b=15\)
2. \(6g+b=15\)  and  \(g+b=45\)
3. \(g+b=15\)  and  \(6g+b=45\)
4. \(g+b=15\)  and  \(g+6b=45\)