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Mechanics, EXT2 EQ-Bank 17

Two light inextensible strings are attached to a horizontal surface and suspended a 10-kilogram object as shown in the diagram below 
 

The tension in the strings are \(T_1\) newtons and \(T_2\) newtons.

  1. Express \(T_1\) in terms of \(T_2\).   (2 marks)

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  2. If the acceleration due to gravity is 9.8 ms\(^{-2}\), determine the exact values of \(T_1\) and \(T_2\), in newtons.   (2 marks)

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a.    \(\text{See Worked Solutions}\)

b.    \(T_1=49 \sqrt{3}, T_2=49\)

Show Worked Solution

a.    \(\text{Resolve forces into horizontal/vertical components:}\)

 
       

\(\text{Horizontal forces are equal.}\)

\(T_1 \cos 60^{\circ}\) \(=T_2 \cos 30^{\circ}\)
\(T_1 \times \dfrac{1}{2}\) \(=T_2 \times \dfrac{\sqrt{3}}{2}\)
\(T_1\) \(=\sqrt{3}\, T_2\)

 

b.    \(\text{Vertical forces are equal.}\)

\(T_1 \sin 60^{\circ}+T_2 \sin 30^{\circ}\) \(=10 \times 9.8\)
\(T_1 \times \dfrac{\sqrt{3}}{2}+T_2 \times \frac{1}{2}\) \(=98\)

 

\(\text {Substitute} \ \ T_1=\sqrt{3}\, T_2 :\)

\(\sqrt{3}\, T_2 \times \dfrac{\sqrt{3}}{2}+T_2 \times \dfrac{1}{2}\) \(=98\)
\(2\, T_2\) \(=98\)
\(T_2\) \(=49 \ \text{newtons}\)

 

\(\therefore T_1=49 \sqrt{3}, \ T_2=49\)

Filed Under: Forces and Further Motion in a Straight Line Tagged With: Band 3, Band 4, smc-7437-50-Resolving Forces

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