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Algebra, STD2 EQ-Bank 11

The amount of water (\(W\)) in litres used by a garden irrigation system varies directly with the time (\(t\)) in minutes that the system operates.

This relationship is modelled by the formula \(W=kt\), where \(k\) is a constant.

The irrigation system uses 96 litres of water when it operates for 24 minutes.

  1. Show that the value of \(k\) is 4.   (1 mark)

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  2. The water tank for the irrigation system contains 650 litres of water. Calculate how many minutes the irrigation system can operate before the tank is empty.   (2 marks)

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Show Answers Only

a.    \(W=kt\)

\(\text{When } W = 96 \text{ and } t = 24:\)

\(96\) \(=k \times 24\)
\(k\) \(=\dfrac{96}{24}\)
\(k\) \(=4\ \text{(as required)}\)

b.     \(162.5\ \text{minutes}\)

Show Worked Solution

a.    \(W=kt\)

\(\text{When } W = 96 \text{ and } t = 24:\)

\(96\) \(=k \times 24\)
\(k\) \(=\dfrac{96}{24}\)
\(k\) \(=4\ \text{(as required)}\)

  
b.    \(W = 4t\)

\(\text{When } W = 650:\)

\(650\) \(=4\times t\)
\(t\) \( =\dfrac{650}{4}\)
  \(=162.5\ \text{minutes}\)

    
\(\therefore\ \text{The irrigation system can operate for } 162.5 \text{ minutes.}\)

Filed Under: Direct Variation and Currency Conversion (Std2-2027) Tagged With: Band 4, Band 5, smc-6249-10-Find k, smc-6249-30-Graphical Solutions, syllabus-2027

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