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Cartesian Plane, SMB-010

The point  `C(-2,3)`  is the midpoint of the interval `AB`, where `B` has coordinates  `(-1,0).`

What are the coordinates of  `A`?  (3 marks)

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`(-3,6)`

Show Worked Solution

`text(Using the midpoint formula):`

`(x_A + x_B)/2` `= x_C` `(y_A + y_B)/2` `= y_C`
`(x_A-1)/2` `= -2` `(y_A + 0)/2` `= 3`
`x_A` `= -3` `y_A` `= 6`

 
`:. A\ text(has coordinates)\ (-3,6).`

Filed Under: Cartesian Plane Tagged With: num-title-ct-pathc, smc-4422-10-Mid-point

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