A tank is initially full. It is drained so that at time `t` seconds the volume of water, `V`, in litres, is given by
`V = 50(1 - t/80)^2` for `0 <= t <= 100`
- How much water was initially in the tank? (1 mark)
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- After how many seconds was the tank one-quarter full? (1 mark)
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- At what rate was the water draining out the tank when it was one-quarter full? (2 marks)
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