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Measurement, STD1 M2 2021 HSC 15

City A is in Sweden and is located at (58°N, 16°E). Sydney, in Australia, is located at (33°S, 151°E).

Robert lives in Sydney and needs to give an online presentation to his colleagues in City A starting at 5:00 pm Thursday, local time in Sweden.

What time and day, in Sydney, should Robert start his presentation?

It is given that 15° = 1 hour time difference. Ignore daylight saving.  (3 marks)

Show Answers Only

`text(2 am Friday)`

Show Worked Solution

`text{Angular difference}\ = 151 – 16 = 135°`

♦♦ Mean mark 25%.

`=>\ text{Time difference}\ = 135/15 = 9\ text(hours)`

`text(Sydney is east of Sweden → ahead)`
 

`text{Presentation time (Sydney)}` `=\ text(5 pm Thurs + 9 hours)`  
  `=\ text(2 am Friday)`  

Filed Under: M2 Working with Time (Y11) Tagged With: Band 5, smc-1102-20-Longitude and Time Differences

Measurement, STD2 M2 SM-Bank 3

An aircraft travels at an average speed of  913 km/h. It departs from a town in Kenya  (0°, 38°E)  on Tuesday at 10 pm and flies east to a town in Borneo  (0°, 113°E).

  1. Calculate the distance (`d`), to the nearest kilometre, between the two towns, using

     

    `d=theta/360 xx 2 pi r`  where  `theta = 75^@`  and  `r=6400` km  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. How long will the flight take? (Answer to the nearest hour.)   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. What will be the day and local time in Borneo when the aircraft arrives? (Ignore time zones.)   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `8378\ text(km)`
  2. `9\ text(hours)`
  3. `text(12 midday on Wednesday)`
Show Worked Solution
i.   `text(Angular difference in longitude)`

`= 113 – 38`

`= 75^@`
 

`:.\ text(Distance)` `= 75/360 xx 2 xx pi xx 6400`
  `= 8377.58…`
  `= 8378\ text(km)\ text{(nearest km)}`

 

ii.    `text(Flight time)` `= text(Distance)/text(Speed)`
    `= 8378/913`
    `= 9.176…`
    `= 9\ text(hours)\ text{(nearest hr)}`

 

iii.   `text(Time Difference)` `= 75 xx 4`
    `= 300\ text(minutes)`
    `= 5\ text(hours)`

 
`text(Kenya is further East)`

COMMENT: NESA Nov-19 syllabus updates … use longitude to calculate time differences (1° = 4 mins).

`=>\ text(Kenya is +5 hours)`
 

`:.\ text(Arrival time in Kenya)`

`= text{10 pm (Tues) + 5 hrs + 9 hrs}\ text{(flight)}`

`= 12\ text(midday on Wednesday)`

Filed Under: M2 Working with Time (Y11), M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, smc-1102-20-Longitude and Time Differences, smc-6305-10-Longitude and Time Differences, smc-776-20-Longitude and Time Differences

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