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Vectors, SPEC2 2021 VCAA 11 MC

Let `underset~i` be a unit vector pointing east and let `underset~j` be a unit vector pointing north.

A group of hikers travels 5 km in the direction south 30° west and then north for 10 km.

The position vector `underset~a` of the group of hikers with respect to the starting point is

  1. `underset~a = -5/2 underset~i - (5sqrt3)/2 underset~j`
  2. `underset~a = -5/2 underset~i + (10 - (5sqrt3)/2)underset~j`
  3. `underset~a = -5/2 underset~i + 10underset~j`
  4. `underset~a = -(5sqrt3)/2 underset~i + 15/2 underset~j`
  5. `underset~a = 5/2 underset~i + (10 + (5sqrt3)/2)underset~j`
Show Answers Only

`B`

Show Worked Solution

`sin30 = x/5 \ => \ x = 5/2`

`cos30 = y/5 \ => \ y = (5sqrt3)/2`

`:. P_1\ text(vector:)\  (-5/2 underset~i, -(5sqrt3)/2 underset~j)`

`:. P_2\ text(vector:)\  (-5/2 underset~i, (10 – (5sqrt3)/2)underset~j)`

`=>\ B`

Filed Under: Basic Concepts and Calculations Tagged With: Band 4, smc-1176-10-Distance between points

Vectors, SPEC2 2019 VCAA 11 MC

Let point `M` have coordinates  `(a, 1,-2)`  and let point `N` have coordinates  `(-3, b,-1)`.

If the coordinates of the midpoint of  `bar(MN)`  are  `(-5, 3/2, c)`  and `a, b` and `c` are real constants, the the values of `a, b` and `c` are respectively

  1. `−13, 2 and −1/2`
  2. `−2, 1/2 and −3`
  3. `−7, −2 and −3/2`
  4. `−2, −1/2 and −3`
  5. `−7, 2 and −3/2`
Show Answers Only

`E`

Show Worked Solution

`M = 1/2 ([(a),(1),(−2)] + [(−3),(b),(−1)]) = 1/2 [(a-3),(1 + b),(−3)]`

`1/2(a-3)` `= −5`
`a-3` `= −10`
`a` `= −7`
`1/2(1 + b)` `= 3/2`
`1 + b` `= 3`
`b` `= 2`
`c` `= −3/2`

 
`=>E`

Filed Under: Basic Concepts and Calculations Tagged With: Band 3, smc-1176-10-Distance between points

Vectors, SPEC2 2012 VCAA 16 MC

The distance between the points  `P(−2 ,4, 3)`  and  `Q(1, −2, 1)`  is

A.   `7`

B.   `sqrt 21`

C.   `sqrt 31`

D.   `11`

E.   `49`

Show Answers Only

`A`

Show Worked Solution
`d` `= sqrt((-2 – 1)^2 + (4 – (-2))^2 + (3 – 1)^2)`
  `= sqrt(9 + 36 + 4)`
  `= 7`

 
`=> A`

Filed Under: Basic Concepts and Calculations Tagged With: Band 3, smc-1176-10-Distance between points

Vectors, SPEC2 2013 VCAA 14 MC

The distance from the origin to the point  `P(7,−1,5sqrt2)`  is

  1. `7sqrt2`
  2. `10`
  3. `6 + 5sqrt2`
  4. `100`
  5. `5sqrt6`
Show Answers Only

`B`

Show Worked Solution
`d` `= sqrt((7 – 0)^2 + (−1 – 0)^2 + (5sqrt2 – 0)^2)`
  `= sqrt(49 + 1 + 25 xx 2)`
  `= 10`

 
`=> B`

Filed Under: Basic Concepts and Calculations Tagged With: Band 3, smc-1176-10-Distance between points

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