`ABCDEFGH` are the vertices of a rectangular prism. --- 5 WORK AREA LINES (style=lined) --- --- 6 WORK AREA LINES (style=lined) ---
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`ABCDEFGH` are the vertices of a rectangular prism. --- 5 WORK AREA LINES (style=lined) --- --- 6 WORK AREA LINES (style=lined) ---
`text(Midpoint)\ AG = ((1/2 (2-2)),(1/2 (text{−2} + 2)),(1/2 (0 + 2))) = ((0), (0), (1))` `text(Midpoint)\ DF = ((1/2 (2-2)),(1/2 (2-2)),(1/2 (0 + 2))) = ((0), (0), (1))` `text(S) text(ince midpoints are the same), AG and DF\ text(intersect.)` `vec (AG) ⋅ vec (DF) = |\ vec (AG)\ | ⋅ |\ vec(DF)\ |\ cos theta` `((text{−4}), (4), (2)) ⋅ ((text{−4}), (text{−4}), (2)) = sqrt 36 sqrt 36 cos theta`
i.
`A(2, text{−2}, 0),`
`G(text{−2}, 2, 2)`
`D(2, 2, 0),`
`F (text{−2}, text{−2}, 2)`
ii.
`vec(AG) = ((text{−2}), (2), (2))-((2), (text{−2}), (0)) = ((text{−4}), (4), (2))`
`vec(DF) = ((text{−2}), (text{−2}), (2))-((2), (2), (0)) = ((text{−4}), (text{−4}), (2))`
`16-16 + 4`
`= 36 cos theta`
`cos theta`
`= 1/9`
`theta`
`= 83.62…`
`= 83^@37′`
i. `A(3, 0 , 0), \ \ G(0, 3, 3)`
`vec(AG)`
`= ((0), (3), (3))-((3), (0), (0)) = ((text{−3}), (3), (3))`
`|\ vec(AG)\ |`
`= sqrt (9 + 9 + 9)`
`= 3 sqrt 3\ text(units)`
ii.
`H (3, 3, 3)`
`vec(BH) = ((3), (3), (3))`
`vec(AG) ⋅ vec(BH)`
`= |\ vec(AG)\ | ⋅ |\ vec(BH)\ |\ cos theta`
`((text{−3}), (3), (3)) ⋅ ((3), (3), (3))`
`= sqrt (9 + 9 + 9) ⋅ sqrt (9 + 9 + 9) cos theta`
`-9 + 9 + 9`
`= 27 cos theta`
`cos theta`
`= 1/3`
`theta`
`= 70.52…`
`= 70^@32′`