Find an antiderivative of `(6 + x)/(x^2 + 4).` (2 marks)
Calculus, SPEC2-NHT 2018 VCAA 9 MC
`int (1-cos(10x))\ dx` is equivalent to
- `int(sin^2 (5x))\ dx`
- `1/2 int(sin^2 (20x))\ dx`
- `int(cos^2 (5x))\ dx`
- `2 int (cos^2 (10x))\ dx`
- `2 int(sin^2 (5x))\ dx`