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Calculus, SPEC1 2012 VCAA 1

Find an antiderivative of  `(6 + x)/(x^2 + 4).`  (2 marks)

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`3 tan^-1(x/2) + 1/2 log_e (x^2 + 4)`

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`int (6 + x)/(x^2 + 4)\ dx`

`= int 6/(x^2 + 4)\ dx + int x/(x^2 + 4)\ dx`

`= 3 int 2/(x^2 + 2^2)\ dx + 1/2 int (2x)/(x^2 + 4)\ dx`

`= 3 tan^-1(x/2) + 1/2 log_e (x^2 + 4)\ \ \ (c=0)`

Filed Under: Partial Fractions and Other Integration (SM) Tagged With: Band 4, smc-2565-70-Other

Calculus, SPEC2-NHT 2018 VCAA 9 MC

`int (1-cos(10x))\ dx`  is equivalent to

  1. `int(sin^2 (5x))\ dx`
  2. `1/2 int(sin^2 (20x))\ dx`
  3. `int(cos^2 (5x))\ dx`
  4. `2 int (cos^2 (10x))\ dx`
  5. `2 int(sin^2 (5x))\ dx`
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`E`

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`int (1-cos(10x))\ dx`

 `= int 1-cos (2xx (5x))\ dx`

`= int 1-(2 cos^2 (5x)-1)\ dx`

`= int 2-2 cos^2 (5x)\ dx`

`= int 2 (1-cos^2 (5x))\ dx`

`= 2 int sin^2 (5x)\ dx`

 
`=>  E`

Filed Under: Partial Fractions and Other Integration (SM) Tagged With: Band 3, smc-2565-70-Other

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