A diagram of a block being pulled by a rope up an inclined plane is shown.
Which free body diagram correctly represents the diagram given?
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A box with weight `W` and subject to a friction force `F` is being pulled up an inclined plane by a force `P`.
The force `R` is the resultant of which two forces?
`D`
→ `R` is used as the resultant of `F` and `N`, usually used to calculate `P` and employ the 3 force rule.
`=>D`
A child and sled with a combined mass of 23 kg are being pulled along a horizontal snow-covered surface using a rope.
The coefficient of static friction between the sled and the snow is 0.14.
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The diagram shows the forces acting on a block on an inclined plane. The block is held in a stationary position by force `P`.
What is the correct equation for the normal force, `N` ?
`A`
The diagram shows a box which is at rest on an inclined ramp. The length of the ramp is 3 m and one end is raised `h` metres off the ground.
The coefficient of friction between the ramp and the box is 0.5.
To what height `(h)` must the ramp be raised for the box to just begin to slide? (3 marks)
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`1.34\ text{m}`
`mu` | `= 0.5 = tan\ theta` | |
`theta` | `= tan^(-1)(0.5)` | |
`= 26.57°` |
`sin(26.57°)` | `= h/3` | |
`:.h` | ` = 3 xx sin(26.57°)` | |
` = 1.34\ text{m}` |
A skateboard rider is at rest at the top of a slope, indicated by point `A` in the diagram.
The combined mass of the rider and skateboard is 80 kg.
Calculate the speed of the rider, in metres per second, at point `B` if the average work done by friction against the skateboard is 55 N. (4 marks)
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`text{Speed} = 14.57\ text{m/s}`
`m= 80\ text{kg}, \ f= 55\ text{N}`
`PE` | `= mgh` | |
`= 80xx10xx27.8` | ||
`= 22\ 240\ text{J}` |
`text{Losses to friction (W):}`
`W` | `= fs` | |
`= 55xx250` | ||
`= 13\ 750\ text{J}` |
`text{Energy used}` | `= PE−text{Frictional losses}` | |
`= 22\ 240−13\ 750` | ||
`= 8490\ text{J}` |
`text{Calculate speed at point B:}`
`1/2×m×v^2` | `= 8490` | |
`0.5×80×v^2` | `= 8490` | |
`v^2` | `= 212.25` | |
`:.v` | `= 14.57\ text{m/s}` |