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Probability, SM-Bank 054

The two spinners shown are used in a game.

2UG 2011 26a1

Each arrow is spun once. The score is the total of the two numbers shown by the arrows.
A table is drawn up to show all scores that can be obtained in this game.

2UG 2011 26a2

  1. What is the value of \(X\) in the table?  (1 mark)

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  2. What is the probability of obtaining a score less than 4?  (1 mark)

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  3. On Spinner \(B\), a 2 is obtained. What is the probability of obtaining a score of 3?  (1 mark)

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a.    \(5\)

b.    \(\dfrac{1}{2}\)

c.    \(\dfrac{2}{3}\)

Show Worked Solution

a.    \(X=2+3=5\)

b.    \(P\text{(score < 4)}=\dfrac{6}{12}=\dfrac{1}{2}\)

c.   \(\text{Given Spinner } B =2\)

\(\text{Possible spins }\rightarrow\ (2 , 1), (2 , 1), (2 , 3)\)

\(P\text{(score = 3)}=\dfrac{2}{3}\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, SM-Bank 053

Two unbiased dice,  \(A\)  and  \(B\), with faces numbered  \(1\),  \(2\),  \(3\),  \(4\),  \(5\) and  \(6\) are rolled.

The numbers on the uppermost faces are noted. This table shows all the possible outcomes.

 
\begin{align}
\textbf{Die B } \
\begin{array}{c }
\textbf{Die A } \\
\begin{array}{c|c|c|c|c|c|c}
\ & 1 & 2 & 3 & 4 & 5 & 6  \\
\hline
\ 1 & 1,1 & 1,2 & 1,3 & 1,4 & 1,5 & 1,6  \\
\hline
\ 2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & 2,6  \\
\hline
\ 3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & 3,6  \\
\hline
\ 4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & 4,6  \\
\hline
\ 5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & 5,6  \\
\hline
\ 6 & 6,1 & 6,2 & 6,3 & 6,4 & 6,5 & 6,6  \\
\end{array}
\end{array}
\end{align}

 

A game is played where the difference between the highest number showing and the lowest number showing on the uppermost faces is calculated.

What is the probability that the difference between the numbers showing on the uppermost faces of the two dice is one?   (2 marks)

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\(\dfrac{5}{18}\)

Show Worked Solution

\begin{align}
\textbf{Die B } \
\begin{array}{c }
\textbf{Die A } \\
\begin{array}{c|c|c|c|c|c|c}
\ & 1 & 2 & 3 & 4 & 5 & 6  \\
\hline
\ 1 & 1,1 & \colorbox{lightblue}{1,2} & 1,3 & 1,4 & 1,5 & 1,6  \\
\hline
\ 2 & \colorbox{lightblue}{2,1} & 2,2 & \colorbox{lightblue}{2,3} & 2,4 & 2,5 & 2,6  \\
\hline
\ 3 & 3,1 & \colorbox{lightblue}{3,2} & 3,3 & \colorbox{lightblue}{3,4} & 3,5 & 3,6  \\
\hline
\ 4 & 4,1 & 4,2 & \colorbox{lightblue}{4,3} & 4,4 & \colorbox{lightblue}{4,5} & 4,6  \\
\hline
\ 5 & 5,1 & 5,2 & 5,3 & \colorbox{lightblue}{5,4} & 5,5 & \colorbox{lightblue}{5,6}  \\
\hline
\ 6 & 6,1 & 6,2 & 6,3 & 6,4 & \colorbox{lightblue}{6,5} & 6,6  \\
\end{array}
\end{array}
\end{align}

 

\(\text{# Outcomes with a difference of 1}\)

\(=10\)

\(\therefore\ P \text{(diff of 1)}=\dfrac{10}{36}=\dfrac{5}{18}\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, SM-Bank 051

In any standard six-sided dice, the sum of the opposite faces is 7.

Milo rolls 3 dice and the total of the top faces is 5.

What is the sum of the three opposite faces?  (2 marks)

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\(16\)

Show Worked Solution

\(\text{Sum of 3 top faces + 3 opposite}\)

\(=3\times 7\)

\(=21\)

\(\therefore\ \text{Sum of 3 opposite faces}\)

\(=21-5\)

\(=16\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, SM-Bank 049

Maxi and Jim are playing a dice game.

They have two standard 6-sided dice.

One of the die is white and the other is grey.

Maxi needs to roll a total of 11 to win.

There are two different ways she can roll a total of 11 as shown.
 
 

Jim has to roll a 6 to win.

How many different ways can Jim roll a total of 6?  (1 mark)

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\(\text{5 different ways.}\)

Show Worked Solution

\(\text{The table below shows the ways a sum of 6 can be rolled.}\)

\(\therefore\ \text{5 different ways.}\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, SM-Bank 038 MC

Bryce has a bag of marbles. 80% of his marbles are red.

Bryce takes a yellow marble from his bag and loses it in a game.

If he takes another marble from the bag without looking, what are the chances it is red?

  1. greater than 80%
  2. equal to 80%
  3. less than 80%
  4. there is not enough information to predict the chance
Show Answers Only

\(A\)

Show Worked Solution

\(\text{There will be greater than 80% chance}\)

\(\text{because there are the same amount of }\)

\(\text{red marbles to be chosen but 1 less}\)

\(\text{marble in the bag.}\)

 
\(\Rightarrow A\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, SM-Bank 030

Luigi spins these two arrows. He then adds the numbers in the sections where the  arrows stop to get the total score.
 

 
How many different ways can Luigi get a total of 7?  (2 marks)

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\(3\)

Show Worked Solution

\(\text{Consider the possibile ways to get 7}\)
 

 
 

\(\therefore\ \text{There are 3 ways to get a total of 7.}\)

Filed Under: Probability Tagged With: num-title-ct-core, smc-4225-45-Multi-stage events

Probability, STD1 S2 2020 HSC 26

Barbara plays a game of chance, in which two unbiased six-sided dice are rolled. The score for the game is obtained by finding the difference between the two numbers rolled. For example, if Barbara rolls a 2 and a 5, the score is 3.

The table shows some of the scores.
 


 

  1. Complete the six missing values in the table to show all possible scores for the game.   (1 mark)
  2. What is the probability that the score for a game is NOT 0?  (2 marks)

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  1.  

     
  2. `frac{5}{6}`
Show Worked Solution

a.     

♦ Mean mark part (b) 47%.
b.       `Ptext{(not zero)}` `= frac{text(numbers) ≠ 0}{text(total numbers)}`
    `= frac{30}{36}`
    `= frac{5}{6}`

 
\(\text{Alternate solution (b)}\)

b.       `Ptext{(not zero)}` `= 1 – Ptext{(zero)}`
    `= 1 – frac{6}{36}`
    `= frac{5}{6}`

Filed Under: Probability, Single and Multi-Stage Events (Std 1) Tagged With: Band 4, Band 5, num-title-ct-core, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-1135-40-Arrays, smc-4225-20-Complementary events, smc-4225-45-Multi-stage events

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