According to Gay-Lussac's Law, the pressure of a gas is directly proportional to which quantity, assuming the volume and the number of moles are constant?
- Volume
- Temperature
- Moles
- Pressure
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According to Gay-Lussac's Law, the pressure of a gas is directly proportional to which quantity, assuming the volume and the number of moles are constant?
\(B\)
→ Gay-Lussac’s Law states that the pressure of a gas is directly proportional to its temperature, provided the volume and number of moles remain constant.
→ This can be written mathematically like \(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\).
\(\Rightarrow B\)
A sealed container of gas is heated, causing the temperature of the gas to increase from 300 K to 450 K, while the volume of the gas remains constant. If the initial pressure of the gas was 120 kPa, what will the new pressure be?
\(A\)
→ Using Gay-Lussac’s Law: \(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\)
\(P_2=\dfrac{P_1T_2}{T_1}=\dfrac{120 \times 450}{300}=180\ \text{kPa}\)
\(\Rightarrow A\)