In a laboratory experiment, white light is passed through a prism and splits into a spectrum of colours.
What is this effect called?
- Diffraction
- Polarisation
- Dispersion
- Interference
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In a laboratory experiment, white light is passed through a prism and splits into a spectrum of colours.
What is this effect called?
\(A\)
\(\Rightarrow A\)
A physics class is investigating the dispersion of white light using a lens, as shown in the diagram below.
The students observe the rays \(\text{K–P}\) that have been refracted by the lens.
Which one of the following correctly identifies the colour, red \(\text{(R)}\), green \(\text{(G)}\) or violet \(\text{(V)}\), of the rays \(\text{K–P}\)?
| \(\textbf{K}\) | \(\textbf{L}\) | \(\textbf{M}\) | \(\textbf{N}\) | \(\textbf{O}\) | \(\textbf{P}\) | |
| \(\textbf{A.}\) | \(\quad \text{R}\quad \) | \(\quad \text{G}\quad \) | \(\quad \text{V}\quad \) | \(\quad \text{V}\quad \) | \(\quad \text{G}\quad \) | \(\quad \text{R}\quad \) |
| \(\textbf{B.}\) | \(\text{V}\) | \(\text{G}\) | \(\text{R}\) | \(\text{R}\) | \(\text{G}\) | \(\text{V}\) |
| \(\textbf{C.}\) | \(\text{V}\) | \(\text{G}\) | \(\text{R}\) | \(\text{V}\) | \(\text{G}\) | \(\text{R}\) |
| \(\textbf{D.}\) | \(\text{V}\) | \(\text{R}\) | \(\text{G}\) | \(\text{G}\) | \(\text{R}\) | \(\text{V}\) |
\(B\)
\(\Rightarrow B\)
A student sets up an experiment involving a source of white light, a glass prism and a screen. The path of a single ray of white light when it travels through the prism and onto the screen is shown in Figure 14. A spectrum of colours is observed by the student on the screen, which is positioned to the right of the prism. --- 5 WORK AREA LINES (style=lined) --- --- 2 WORK AREA LINES (style=lined) ---
a. The observed effect is dispersion. b. Point \(X\) is red. Point \(Y\) is blue/purple.
a. The observed effect is dispersion. b. Point \(X\) is red. Point \(Y\) is blue/purple.
A Physics class is investigating the dispersion of white light using a triangular glass prism.
Which one of the following diagrams best shows the principle of dispersion?
\(A\)
\(\Rightarrow A\)
A ray of green light from a light-emitting diode (LED) strikes the surface of a tank of water at an angle of 40.00° to the surface of the water, as shown in diagram below. The ray arrives at the base of the tank at point \(\text{X}\). The depth of the water in the tank is 80.00 cm. The refractive index of green LED light in water is 1.335
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a. \(OX=56\ \text{cm}\)
b.
\begin{array} {|c|c|c|}
\hline
\rule{0pt}{2.5ex}\text{Light to the left of point X}\rule[-1ex]{0pt}{0pt} & \text{Light at point X} & \text{Light to the right of point X} \\
\hline
\rule{0pt}{2.5ex}\text{Blue/Purple}\rule[-1ex]{0pt}{0pt} & \text{Green} & \text{Red} \\ \text{(lower wavelength)} & & \text{(higher wavelength)} \\
\hline
\end{array}
a. \(\text{Using Snell’s Law:}\)
| \(n_1 \sin \theta_1\) | \(=n_2 \sin \theta_2\) | |
| \(\sin \theta_2\) | \(=\dfrac{n_1 \sin \theta_1}{n_2}\) | |
| \( \theta_2\) | \(= \sin^{-1}\Big{(}\dfrac{1 \times \sin 50^{\circ}}{1.335} \Big{)}=35^{\circ}\) |
| \(\tan35^{\circ}\) | \(=\dfrac{OX}{80}\) | |
| \(OX\) | \(=80\times \tan35^{\circ}=56\ \text{cm}\) |
b.
\begin{array} {|c|c|c|}
\hline
\rule{0pt}{2.5ex}\text{Light to the left of point X}\rule[-1ex]{0pt}{0pt} & \text{Light at point X} & \text{Light to the right of point X} \\
\hline
\rule{0pt}{2.5ex}\text{Blue/Purple}\rule[-1ex]{0pt}{0pt} & \text{Green} & \text{Red} \\ \text{(lower wavelength)} & & \text{(higher wavelength)} \\
\hline
\end{array}
What happens to white light when it hits a red surface? (2 marks)
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