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PHYSICS, M4 EQ-Bank 5

A positive test charge of +4.0 \(\mu\)C is placed between two parallel plates with a uniform electric field of 45 N/C. These plates are separated by 0.5 m, and the charge moves a distance of 0.2 m from point A to point B.
 

  1. Determine the magnitude and direction of the force on the charge.   (2 marks)

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  1. Find the potential difference between point A and point B.   (1 mark)

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  1. How much work does the electric field do on the charge during this movement?   (1 mark)

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Show Answers Only

a.    \( 1.8 \times 10^{-4}\ \text{N}\ \text{to the right}\)

b.    \(9\ \text{V}\)

c.    \(3.6 \times 10^{-5}\ \text{J}\)

Show Worked Solution

a.    \(F=qE = 4.0 \times 10^{-6} \times 45 = 1.8 \times 10^{-4}\ \text{N}\ \text{to the right}\)
 

b.    \(V = Ed = 45 \times 0.2 = 9\ \text{V}\)
 

c.    \(W= qEd = 4 \times 10^{-6} \times 45 \times 0.2 = 3.6 \times 10^{-5}\ \text{J}\)

Filed Under: Electrostatics Tagged With: Band 3, Band 4, smc-4283-10-Electric fields, smc-4283-30-Forces on charges, smc-4283-45-Work Done

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