Calculate the value(s) of `p` given that the points `(p,3)` and `(1,p)` are exactly 10 units apart. (3 marks)
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Calculate the value(s) of `p` given that the points `(p,3)` and `(1,p)` are exactly 10 units apart. (3 marks)
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`p=9\ text{or}\ -5`
`(p,3),\ \ (1,p)`
`text{Using the distance formula:}`
`d` | `=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}` | |
`10` | `=sqrt{(p-1)^2+(3-p)^2}` | |
`10` | `=sqrt{p^2-2p+1+9-6p+p^2}` | |
`10` | `=sqrt{2p^2-8p+10}` | |
`100` | `=2p^2-8p+10` | |
`0` | `=2p^2-8p-90` | |
`0` | `=p^2-4p-45` | |
`0` | `=(p-9)(p+5)` |
`:.p=9\ text{or}\ -5`
Calculate the distance between the points `(2,-3)` and `(-5,4)`.
Round your answer to the nearest tenth. (2 marks)
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`9.9\ text{units}`
`(2,-3),\ \ (-5,4)`
`text{Using the distance formula:}`
`d` | `=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}` | |
`=sqrt{(2-(-5))^2+(-3-4)^2}` | ||
`=sqrt{49+49}` | ||
`=sqrt{98}` | ||
`=9.899…` | ||
`=9.9\ text{units (nearest tenth)}` |
Calculate the distance between the points `(6,-5)` and `(0,3)`. (2 marks)
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`10\ text{units}`
`(6,-5),\ \ (0,3)`
`text{Using the distance formula:}`
`d` | `=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}` | |
`=sqrt{(6-0)^2+(-5-3)^2}` | ||
`=sqrt{36+64}` | ||
`=sqrt{100}` | ||
`=10\ text{units}` |
Calculate the distance between the point `(-6,2)` and the origin.
Give your answer in exact form. (2 marks)
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`2sqrt{10}\ \ text{units}`
`(-6,2),\ \ (0,0)`
`text{Using the distance formula:}`
`d` | `=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}` | |
`=sqrt{(-6-0)^2+(2-0)^2}` | ||
`=sqrt{36+4}` | ||
`=sqrt{40}` | ||
`=2sqrt{10}\ \ text{units}` |