Find the centre and radius of the circle with the equation
`x^2+6x+y^2-y+3=0` (2 marks)
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Find the centre and radius of the circle with the equation
`x^2+6x+y^2-y+3=0` (2 marks)
`text{Centre}\ (-3,1/2),\ text{Radius}\ = 5/2`
`x^2+6x+y^2-y+3` | `=0` | |
`x^2+6x+9+y^2-y+1/4-25/4` | `=0` | |
`(x+3)^2+(y-1/2)^2` | `=25/4` | |
`(x+3)^2+(y-1/2)^2` | `=(5/2)^2` |
`text{Centre}\ (-3,1/2),\ text{Radius}\ = 5/2`
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Find the centre and radius of the circle with the equation
`x^2+ y^2+8y= 0` (2 marks)
`text(Centre)\ (0,-4)`
`text(Radius = 4)`
`x^2+ y^2+8y` | `= 0` |
`x^2+ y^2+8y+16-16` | `= 0` |
`x^2+(y+4)^2` | `= 4^2` |
`:.\ text(Centre)\ (0,-4)`
`:.\ text(Radius = 4)`
Find the centre and radius of the circle with the equation
`x^2+10x + y^2-6y+33 = 0` (2 marks)
`text(Centre)\ (-5,3)`
`text(Radius = 1)`
`x^2+10x + y^2-6y+33` | `= 0` |
`x^2+10x + 25 + y^2-6y+9-1` | `= 0` |
`(x+5)^2 + (y-3)^2` | `= 1` |
`:.\ text(Centre)\ (-5,3)`
`:.\ text(Radius = 1)`
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a. `(x+3)^2 + (y+2)^2 = 3^2`
`:.\ text(Centre:)\ (-3,-2)\text(, Radius:)\ 3`
b.
a. | `x^2+6x+y^2+4y+4` | `=0` |
`x^2+6x+9+y^2+4y+4-9` | `=0` | |
`(x+3)^2+(y+2)^2` | `=3^2` |
`:.\ text(Centre:)\ (-3,-2)\text(, Radius:)\ 3`
b.
Find the centre and radius of the circle with the equation
`x^2-12x + y^2 + 2y-12 = 0` (2 marks)
`text(Centre)\ (6, −1)`
`text(Radius = 7)`
`x^2-12x + y^2 + 2y-12` | `= 0` |
`(x-6)^2 + (y + 1)^2-36-1-12` | `= 0` |
`(x-6)^2 + (y + 1)^2` | `= 49` |
`:.\ text(Centre)\ (6, −1)`
`:.\ text(Radius = 7)`
A circle with centre `(a,-2)` and radius 5 units has equation
`x^2-6x + y^2 + 4y = b` where `a` and `b` are real constants.
The values of `a` and `b` are respectively
`B`
`x^2-6x + y^2 + 4y=b`
`text(Completing the squares:)`
`x^2-6x + 3^2-9 + y^2 + 4y + 2^2-4` | `= b` |
`(x-3)^2 + (y + 2)^2-13` | `= b` |
`(x-3)^2 + (y + 2)^2` | `= b + 13` |
`:. a=3`
`:. b+13=25\ \ =>\ \ b=12`
`=> B`