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Algebra, STD2 EQ-Bank 16

It is known that a quantity \(N\) varies directly with another quantity \(Q\).

The relationship can be modelled by the equation  \(N= k \times Q\), where \(k\) is a constant.

If \(N = 18\)  when  \(Q=4:\)

  1. Show the value of  \(k=4.5\).   (1 mark)

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  2. Hence find the value of \(Q\) when  \(N=63\).  (1 mark)

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a.    \(\text{Using}\ \ N=k \times Q:\)

\(18= k \times 4\ \ \Rightarrow\ \ k=\dfrac{18}{4}=4.5\)

b.    \(Q=14\)

Show Worked Solution

a.    \(\text{Using}\ \ N=k \times Q:\)

\(18= k \times 4\ \ \Rightarrow\ \ k=\dfrac{18}{4}=4.5\)
 

b.    \(\text{Find}\ Q\ \text{when}\ \ N=63:\)

\(63\) \(=4.5 \times Q\)  
\(Q\) \(=\dfrac{63}{4.5}=14\)  

Filed Under: Direct Variation, Direct Variation Tagged With: Band 3, smc-6249-10-Find k, smc-6249-20-Algebraic, smc-6514-10-Find k, smc-6514-20-Algebraic

Algebra, STD2 EQ-Bank 17

Two quantities, \(M\) and \(t\), have a relationship such that \(M\) varies directly with \(t\) and  \(M=2.4\)  when  \(t=8\).

Find the value of \(t\) when  \(M=5.1\).   (2 marks)

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\(t=17\)

Show Worked Solution

\(M \propto t \ \ \Rightarrow \ \ M=kt\)

\(\text{Given} \ \ M=2.4 \ \ \text{when} \ \ t=8:\)

\(2.4=8k \ \ \Rightarrow \ \ k=\dfrac{2.4}{8}=0.3\)

\(\text{When} \ \ M=5.1:\)

\(5.1\) \(=0.3 \times t\)  
\(t\) \(=\dfrac{5.1}{0.3}=17\)  

Filed Under: Direct Variation, Direct Variation Tagged With: Band 4, smc-6249-20-Algebraic, smc-6514-20-Algebraic

Algebra, STD2 EQ-Bank 18

\(F\) varies directly with \(m\) and \(F=14\) when \(m=3.5\).

Find the value of \(m\) when \(F=50\).   (2 marks)

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\(m=12.5\)

Show Worked Solution

\(F \propto m \ \ \Rightarrow \ \ F=km\)

\(\text{Given} \ \ F=14 \ \ \text{when} \ \ m=3.5:\)

\(14=3.5k \ \ \Rightarrow \ \ k=4\)

\(\text{When} \ \ F=50:\)

\(50\) \(=4 \times m\)  
\(m\) \(=\dfrac{50}{4} = 12.5\)  

Filed Under: Direct Variation, Direct Variation Tagged With: Band 4, smc-6249-20-Algebraic, smc-6514-20-Algebraic

Algebra, STD2 EQ-Bank 4 MC

\(d\) varies directly with \(h\) and it is known that  \(d=1.2\)  when  \(h=5\).

The value of \(h\) when  \(d=48\)  is

  1. \(11.52\)
  2. \(57.6\)
  3. \(200\)
  4. \(240\)
Show Answers Only

\(C\)

Show Worked Solution

\(d \propto h \ \ \Rightarrow \ \ d=k \times h\)

\(\text{Find \(k\) given \(\ d=1.2\)  when \(\ h=5\):}\)

\(1.2\) \(=5 \times k\)  
\(k\) \(=\dfrac{1.2}{5}=0.24\)  

 
\(\text{Find} \ h \ \text{when} \ \ d=48:\)

\(48\) \(=0.24 \times h\)  
\(h\) \(=\dfrac{48}{0.24}=200\)  

 
\(\Rightarrow C\)

Filed Under: Direct Variation, Direct Variation Tagged With: Band 4, smc-6249-20-Algebraic, smc-6514-20-Algebraic

Algebra, STD2 EQ-Bank 1 MC

\(Q\) varies directly with \(r\) and  \(Q=2\) when  \(r=16\).

The value of \(r\) when  \(Q=13\)  is

  1. \(1.625\)
  2. \(26\)
  3. \(76\)
  4. \(104\)
Show Answers Only

\(D\)

Show Worked Solution

\(Q \propto r \ \Rightarrow \ Q=kr\)

\(\text{Find \(k\) given \(\ Q=2\) given \(\ r=16\):}\)

\(2=16 \times k \ \Rightarrow \ k=\dfrac{1}{8}\)

\(\text{Find \(r\) when \(\ Q=13:\)}\)

\(13\) \(=\dfrac{1}{8} \times r\)  
\(r\) \(=13 \times 8=104\)  

 
\(\Rightarrow D\)

Filed Under: Direct Variation, Direct Variation Tagged With: Band 4, smc-6249-20-Algebraic, smc-6514-20-Algebraic

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