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Functions, 2ADV EQ-Bank 12

The braking distance of a car, in metres, is directly proportional to the square of its speed in km/h, and can be represented by the equation

`text{braking distance}\ = k xx text{(speed)}^2`

where `k` is the constant of variation.

The braking distance for a car travelling at 50 km/h is 20 m.

  1. Find the value of `k`.   (2 marks)

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  2. What is the braking distance when the speed of the car is 90 km/h?   (1 mark)

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a.    `k=0.008`

b.    `64.8\ text{m}`

Show Worked Solution

a.  `text{braking distance}\ = k xx text{(speed)}^2`

`20` `=k xx 50^2`  
`k` `=20/50^2=0.008`  

 
b.    `text{Find}\ d\ text{when speed = 90 km/h:}`

`d=0.008 xx 90^2=64.8\ text{m}`

Filed Under: Direct and Inverse Variation Tagged With: Band 3, smc-6383-10-\(\propto kx^{n}\), smc-6383-40-Stopping Distance

Functions, 2ADV EQ-Bank 9

It is known that the volume of a hailstone \((V)\) is directly proportional to the cube of its radius \((r)\).

A hailstone with a radius of 1.25 cm has a volume of 8.2 cm\(^3\).

  1. Find the equation relating \(V\) and \(r\).   (2 marks)

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  2. What is the expected radius of a hailstone with a volume of 51.1 cm\(^3\) ? Give your answer to 1 decimal place.   (1 mark)

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a.    \(V=4.1984 \times r^{3}\)

b.    \(2.3\ \text{cm (2 d.p.)}\)

Show Worked Solution

a.    \(V \propto r^3 \ \Rightarrow \ V=kr^3\)

\(\text{Find} \ k \ \text{given} \ \ V=8.2 \ \ \text{when}\ \  r=1.25:\)

\(8.2\) \(=k \times 1.25^3\)
\(k\) \(=\dfrac{8.2}{1.25^3}=4.1984\)

 
\(\therefore V=4.1984 \times r^{3}\)

  

b.    \(\text{Find \(r\) when \(\ V=51.1\):}\)

\(51.1\) \(=4.1984 \times r^3\)
\(r\) \(=\sqrt[3]{\dfrac{51.1}{4.1984}}=2.3\ \text{cm (1 d.p.)}\)

Filed Under: Direct and Inverse Variation Tagged With: Band 4, smc-6383-10-\(\propto kx^{n}\), smc-6383-50-Real World Examples

Functions, 2ADV EQ-Bank 7

Energy \((E)\) stored in a spring, measured in joules, varies directly with the square of its compression distance \(d\), measured in centimetres.

When a spring is compressed by 4 cm, it stores 48 joules of energy.

How much energy is stored when the spring is compressed by 7 cm?   (3 marks)

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\(\text{147 joules}\)

Show Worked Solution

\(E \propto d^2 \ \Rightarrow \ E=k d^2\)

\(\text{Find \(k\) given  \(\ E=48 \ \)  when  \(\ d=4\):}\)

\(48\) \(=k \times 4^2\)
\(k\) \(=3\)

 
\(\text{Find \(E\) when  \(\ d=7\):}\)

\(E=3 \times 7^2=147 \ \text{joules}\)

Filed Under: Direct and Inverse Variation Tagged With: Band 3, smc-6383-10-\(\propto kx^{n}\), smc-6383-50-Real World Examples

Functions, 2ADV F1 EQ-Bank 8

Jacques is a marine biologist and finds that the mass of a crab is directly proportional to the cube of the diameter of its shell.

If a crab with a shell diameter of 15 cm weighs 680 grams, what will be the diameter of a crab that weighs 1.1 kilograms? Give your answer to 1 decimal place.  (2 marks)

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`17.6\ text(cm)`

Show Worked Solution
`M` `prop d^3`  
`M` `= kd^3`  

 
`text(When)\ \ M=680, \ d=15`

`680` `=k xx 15^3`  
`k` `=0.201481…`  

 
`text(Find)\ \ d\ \ text(when)\ \ M=1100:`

`1100` `=0.20148… xx d^3`  
`d` `=root3(1100/(0.20148…))`  
  `=17.608…`  
  `=17.6\ text{cm  (to 1 d.p.)}`  

Filed Under: Direct and Inverse Variation, Further Functions and Relations (Y11) Tagged With: Band 4, smc-6383-10-\(\propto kx^{n}\), smc-987-60-Proportional

Functions, 2ADV F1 EQ-Bank 27

The stopping distance of a car on a certain road, once the brakes are applied, is directly proportional to the square of the speed of the car when the brakes are first applied.

A car travelling at 70 km/h takes 58.8 metres to stop.

How far does it take to stop if it is travelling at 105 km/h?  (3 marks)

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`132.3\ text(metres)`

Show Worked Solution

`text(Let)\ \ d\ text(= stopping distance)`

`d \prop s^2\ \ =>\ \ d = ks^2`
 

`text(Find)\ k,`

`58.8` `= k xx 70^2`
`k` `= 58.8/(70^2)= 0.012`

 
`text(Find)\ \ d\ \ text(when)\ \ s = 105:`

`d` `= 0.012 xx 105^2`
  `= 132.3\ text(metres)`

Filed Under: Direct and Inverse Variation, Further Functions and Relations (Y11) Tagged With: Band 4, smc-6383-10-\(\propto kx^{n}\), smc-6383-40-Stopping Distance, smc-987-60-Proportional

Functions, 2ADV F1 EQ-Bank 26

Fuifui finds that for Giant moray eels, the mass of an eel is directly proportional to the cube of its length.

An eel of this species has a length of 25 cm and a mass of 4350 grams.

What is the expected length of a Giant moray eel with a mass of 6.2 kg? Give your answer to one decimal place.  (3 marks)

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`28.1\ text{cm}`

Show Worked Solution

`text(Mass) prop text(length)^3`

`m = kl^3`
 

`text(Find)\ k:`

`4350` `= k xx 25^3`
`k` `= 4350/25^3`
  `= 0.2784`

 
`text(Find)\ \ l\ \ text(when)\ \ m = 6200:`

`6200` `= 0.2784 xx l^3`
`l^3` `= 6200/0.2784`
`:. l` `= 28.13…`
  `= 28.1\ text{cm  (to 1 d.p.)}`

Filed Under: Direct and Inverse Variation, Further Functions and Relations (Y11) Tagged With: Band 4, smc-6383-10-\(\propto kx^{n}\), smc-987-60-Proportional

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