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Combinatorics, EXT1 A1 EQ-Bank 8

Show `\ ^nC_k = \ ^nC_(n-k)`.  (1 mark)

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`text(See Worked Solutions)`

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`\ ^nC_k = (n!)/((n-k)!k!)`

`\ ^nC_(n-k)` `= (n!)/((n-(n-k))!(n-k)!)`
  `= (n!)/(k!(n-k)!)`
  `= \ ^nC_k`

Filed Under: Binomial Expansion (Ext1), The Binomial Theorem (Y11) Tagged With: Band 3, smc-1088-30-Proofs, smc-6639-40-Proof of Pascal Identity

Combinatorics, EXT1 A1 EQ-Bank 7

Show `\ ^nC_k = \ ^(n-1)C_(k-1) + \ ^(n-1)C_k`.   (2 marks)

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`text(LHS) = (n!)/((n-k)!k!)`

`text(RHS)` `= ((n-1)!)/((n-1-(k-1))!(k-1)!) + ((n-1)!)/((n-1-k)!k!)`
  `= ((n-1)!k)/((n-k)!(k-1)!k) + ((n-1)!(n-k))/((n-k-1)!(n-k)k!)`
  `= ((n-1)!k)/((n-k)!k!) + ((n-1)!(n-k))/((n-k)!k!)`
  `= ((n-1)!(k + n-k))/((n-k)!k!)`
  `= (n!)/((n-k)!k!)`
  `=\ text(LHS)`

Filed Under: Binomial Expansion (Ext1), The Binomial Theorem (Y11) Tagged With: Band 4, smc-1088-30-Proofs, smc-6639-40-Proof of Pascal Identity

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