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Functions, EXT1 F1 2020 SPEC1 4

Solve the inequality  `3-x > 1/|x-4|`  for `x`, expressing your answer in interval notation.   (3 marks)

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`x ∈ (-oo, (7-sqrt 5)/2)`

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`3-x > 1/|x-4|\ =>\ |x-4| (3-x) > 1`
 

`text(If)\ \ x-4 > 0\ =>\ x > 4:`

`(x-4) (3-x)` `> 1`
`3x-x^2-12 + 4x` `> 1`
`-x^2 + 7x-13` `> 0`

 
`Delta = 7^2-4 ⋅ 1 ⋅ 13 = -3 < 0`

`=>\ text(No Solutions)`
 

`text(If)\ \ x-4 < 0\ =>\ x < 4:`

`-(x-4) (3-x)` `> 1`
`x^2-7x + 12` `> 1`
`x^2-7x + 11` `> 0`

 
`x= (7 +- sqrt(7^2-4 ⋅ 1 ⋅ 11))/2= (7 +- sqrt 5)/2`
 

`text(Combining solutions:)`

`(x < (7-sqrt 5)/2  ∪ \ x > (7 + sqrt 5)/2)  nn \ x < 4`

`x ∈ (-oo, (7-sqrt 5)/2)`

Filed Under: Inequalities, Inequalities Tagged With: Band 4, smc-1033-20-Absolute Value, smc-1033-50-Interval notation, SMc-6643-20-Absolute Value, smc-6643-50-Interval Notation

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