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Graphs, MET2 2011 VCAA 1 MC

The midpoint of the line segment joining  `text{(0, − 5)}`  to  `(d,0)`  is

  1. `(d/2,−5/2)`
  2. `(0,0)`
  3. `((d - 5)/2,0)`
  4. `(0,(5 - d)/2)`
  5. `((5 + d)/2,0)`
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`=> A`

Show Worked Solution
`text(Midpoint)` `= ((0 + d)/2,(−5 + 0)/2)`
  `= (d/2,−5/2)`

 
`=> A`

Algebra, MET2 2013 VCAA 2 MC

The midpoint of the line segment that joins  `text{(1, −5)}`  to  `(d, 2)`  is

  1. `((d + 1)/2, -3/2)`
  2. `((1 - d)/2, -7/2)`
  3. `((d - 4)/2, 0)`
  4. `(0, (1 - d)/3)`
  5. `((5 + d)/2, 2)`
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`A`

Show Worked Solution
`text(Midpoint)` `= ((d + 1)/2, (2 + (-5))/2)`
  `= ((d + 1)/2, -3/2)`

`=>   A`