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v1 Measurement, STD2 M1 2014 HSC 27c

A swimming pool is in the shape of a rectangle with a semicircle at each end, as shown.

The pool is 7000 mm long, 4000 mm wide, and has a depth of 2100 mm.  
  

How much water is needed to fill the pool, to the nearest litre?   (4 marks) 

--- 10 WORK AREA LINES (style=lined) ---

Show Answers Only

`51 \ 589 \ text(L)`

Show Worked Solution

`V = Ah` 

♦ Mean mark 41%
STRATEGY: Adjusting measurements to metres makes the final conversion to litres simple.

`text(Finding Area of base)`

`text(Semi-circles have radius 2000 mm) = 2 \ text(m)`

`:.\ text(Area of 2 semicircles)`

`=2 xx 1/2 xx pi r^2`

`= pi xx 2^2`

`= 12.56 \ text(m)^2`
 

`text(Area of rectangle)`

`= l xx b`

`= (7-2 xx 2) xx 4`

`= 12\ text(m)^2`

 

`:.\ text(Volume)` `= Ah`
  `= (12.56… + 12) xx 2.1`
  `= 51.589…\ text(m)^3`
  `= 51 \ 589 \ text(L)\ \ text{(using 1m³} = 1000\ text{L)}`
   

Filed Under: Perimeter, Area and Volume (Std2-X) Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-4235-20-Cylinders, smc-4235-80-Capacity in litres, smc-798-50-Volume (Circular Measure), smc-798-60-Water Catchment

v1 Measurement, STD2 M1 2010 HSC 17 MC

During a heavy storm, 2.4 hectares of farmland received rainfall to a depth of 12 cm.

How many kilolitres of rainwater fell on the farmland? (1 hectare = 10 000 m²)

  1. 2.88 kL
  2. 2880 kL
  3. 288 000 kL
  4. 2 880 000 kL
Show Answers Only

`B`

Show Worked Solution
♦♦ Mean mark 36%
NOTE: The unit conversion 1 m³ = 1000 L is contained in the Formulae and Data sheet given out in the exam.
`text(Area of farmland)` `=2.4xx10\ 000`
  `=24\ 000\ text(m²)`
`text(Volume)` `=Ah`
  `=24\ 000xx0.12`
  `=2880\ text(m³)`

 

`text{1 m³}` `=1000\ text(L)=1\ text(kL)`
`:.\ text(Volume)` `=2880\ text(kL)`

`=>B`

Filed Under: Perimeter, Area and Volume (Std2-X) Tagged With: Band 5, smc-798-40-Volume, smc-798-60-Water Catchment

v1 Measurement, STD2 M1 SM-Bank 26 MC

A rectangular swimming pool measures 15 m by 8 m and has an average depth of 1.8 m. The pool is being filled at a rate of 250 litres per minute.

What is the volume of water needed to fill the pool completely?

(1 m³ = 1000 L)

  1. 216 L
  2. 2 160 L
  3. 21 600 L
  4. 216 000 L
Show Answers Only

`=>\ text(D)`

Show Worked Solution

`text(Volume of pool in m³:)`

`text(Vol)` `= l xx w xx h`
  `= 15 xx 8 xx 1.8`
  `= 216 \ text(m³)`
  `= 216 xx 1000 \ text(L)`
  `= 216\ 000 \ text(L)`

`=>\ text(D)`

Filed Under: Perimeter, Area and Volume (Std2-X) Tagged With: Band 4, smc-798-40-Volume, smc-798-60-Water Catchment

v1 Measurement, STD2 M1 2016 HSC 30a

The area of a school roof is 45 m². All rain that falls on the roof flows into a storage tank.

How many litres of water are collected in the tank when 25 mm of rain falls?   (2 marks)

--- 5 WORK AREA LINES (style=lined) ---

Show Answers Only

`1125\ \text{L}`

Show Worked Solution
`text{Volume}` `= A × h`
  `= 45 × (25 ÷ 1000)`
  `= 1.125\ \text{m}^3`
  `= 1125\ \text{L}`

Filed Under: Perimeter, Area and Volume (Std2-X) Tagged With: Band 5, smc-798-40-Volume, smc-798-60-Water Catchment

Measurement, STD2 M1 2022 HSC 28

A dam is in the shape of a triangular prism which is 50 m long, as shown.

Both ends of the dam, `A B C` and `D E F`, are isosceles triangles with equal sides of length 25 metres. The included angles `B A C` and `E D F` are each `150^@`.

 
     

Calculate the number of litres of water the dam will hold when full.  (4 marks)

--- 8 WORK AREA LINES (style=lined) ---

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`7\ 812\ 500\ text{L}`

Show Worked Solution

`V=Ah`

`text{Use sine rule to find}\ A:`

`A` `=1/2 ab\ sinC`  
  `=1/2 xx 25 xx 25 xx sin150^@`  
  `=156.25\ text{m}^2`  

 

`:.V` `=156.25 xx 50`  
  `=7812.5\ text{m}^3`  

 

`text{S}text{ince 1 m³ = 1000 litres:}`

`text{Dam capacity}` `=7812.5 xx 1000`  
  `=7\ 812\ 500\ text{L}`  

♦♦ Mean mark 33%.

Filed Under: Perimeter, Area and Volume (Std 2), Perimeter, Area and Volume (Std2-2027), Volume Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-4235-10-Prisms, smc-4235-70-Sine rule (Area), smc-6304-40-Volume, smc-6304-60-Water Catchment, smc-798-40-Volume, smc-798-60-Water Catchment

Measurement, STD2 M1 SM-Bank 26 MC

During a flood, 12.5 hectares of land was covered by water to a depth of 30 cm.

How many kilolitres of water covered the land?

(1 hectare = 10 000 m² and 1 m³ = 1000 L)

  1. 3.75 kL
  2. 37.5 kL
  3. 37 500 kL
  4. 37 500 000 kL
Show Answers Only

`=>\ text(C)`

Show Worked Solution

`text(Volume of water in m³:)`

`text(Vol)` `= Ah`
  `= 12.5 xx 10\ 000 xx 30\ text(cm)`
  `= 12.5 xx 10\ 000 xx 0.3`
  `= 37\ 500 \ text(m³)`
  `= 37\ 500\ text(kL)`

 
`=>\ text(C)`

Filed Under: Perimeter, Area and Volume (Std 2), Perimeter, Area and Volume (Std2-2027) Tagged With: Band 4, smc-6304-40-Volume, smc-6304-60-Water Catchment, smc-798-40-Volume, smc-798-60-Water Catchment

Measurement, STD2 M1 2016 HSC 30a

The area of a roof is 30 m². Any rain that falls on the roof flows directly onto a garden.

Calculate how many litres of water flow onto the garden when 20 mm of rain falls on the roof.  (2 marks)

Show Answers Only

`600\ text(L)`

Show Worked Solution
♦♦ Mean Mark 27%.
STRATEGY: Converting 20 mm into metres as a 1st step is an efficient approach here.
`text(Volume)` `= Ah`
  `= 30 xx 20/1000`
  `= 0.6\ text(m³)`
  `= 600\ text(L)`

Filed Under: Areas and Volumes (Harder), FS Resources, Perimeter, Area and Volume (Std 2), Perimeter, Area and Volume (Std2-2027) Tagged With: Band 5, smc-6304-40-Volume, smc-6304-60-Water Catchment, smc-798-40-Volume, smc-798-60-Water Catchment

Measurement, STD2 M1 2014 HSC 27c

The base of a water tank is in the shape of a rectangle with a semicircle at each end, as shown.

The tank is 1400 mm long, 560 mm wide, and has a height of 810 mm.  
  

What is the capacity of the tank, to the nearest litre?   (4 marks) 

--- 10 WORK AREA LINES (style=lined) ---

Show Answers Only

`581\ text(L)`

Show Worked Solution

`V = Ah` 

♦ Mean mark 41%
STRATEGY: Adjusting measurements to metres makes the final conversion to litres simple.

`text(Finding Area of base)`

`text(Semi-circles have radius 280 mm) = 0.28\ text(m)`

`:.\ text(Area of 2 semicircles)`

`=2 xx 1/2 xx pi r^2`

`= pi xx (0.28)^2`

`= 0.2463…\ text(m)^2`
 

`text(Area of rectangle)`

`= l xx b`

`= (1.4-2 xx 0.28) xx 0.56`

`= 0.4704\ text(m)^2`

 

`:.\ text(Volume)` `= Ah`
  `= (0.2463… + 0.4704) xx 0.810`
  `= 0.580527…\ text(m)^3`
  `= 580.527…\ text(L)\ \ text{(using 1m³} = 1000\ text{L)}`
  `= 581\ text(L)\ text{(nearest L)}`

Filed Under: Areas and Volumes (Harder), FS Resources, Perimeter, Area and Volume (Std 2), Perimeter, Area and Volume (Std2-2027), Volume Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-4235-20-Cylinders, smc-4235-80-Capacity in litres, smc-6304-50-Volume (Circular Measure), smc-6304-60-Water Catchment, smc-798-50-Volume (Circular Measure), smc-798-60-Water Catchment

Measurement, STD2 M1 2010 HSC 17 MC

During a flood 1.5 hectares of land was covered by water to a depth of  17 cm.

How many kilolitres of water covered the land?   (1 hectare = 10 000 m²)  

  1.    2.55 kL
  2.    2550 kL
  3.    255 000 kL
  4.    2 550 000 kL
Show Answers Only

`B`

Show Worked Solution
♦♦ Mean mark 34%
NOTE: The unit conversion 1 m³ = 1000 L  is contained in the Formulae and Data sheet given out in the exam.
`text(Area covered)` `=1.5xx10\ 000`
  `=15\ 000\ text(m²)`
`text(Volume)` `=Ah`
  `=15\ 000xx0.17`
  `=2550\ text(m³)`

 

`text{1 m³}` `=1000\ text(L)=1\ text(kL)`
`:.\ text(Volume)` `=2550\ text(kL)`

`=>B`

Filed Under: Areas and Volumes (Harder), Perimeter, Area and Volume (Std 2), Perimeter, Area and Volume (Std2-2027) Tagged With: Band 5, smc-6304-40-Volume, smc-6304-60-Water Catchment, smc-798-40-Volume, smc-798-60-Water Catchment

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